C4H10 ↔ C2H4 + C2H6 at 700K For the products of the reaction, compute the change...

C4H10 ↔ C2H4 + C2H6 at 700K

For the products of the reaction, compute the change in enthalpy from 298K to 700K

Expert Solution

From the Heat capacity of Gases in the Ideal-gas state table:

Chemical species	A	10³ B	10⁶ C
C4H10	1.935	36.915	-11.402
C2H4	1.424	14.394	-4.392
C2H6	1.131	19.2250	-5.561

By energy balance:

As change in enthalpy of the products is asked.

A = 1.424 + 1.131 = 2.555

B = [19.225 + 14.394 ] x 10^-3 = 33.619 x 10^-3

C = [(-5.561) + (-4.392) ] x 10^-6 = -9.953 x 10^-6

Amanda K answered 2 years ago

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