Question

In: Math

A survey reported that 37% of people plan to spend more on eating out after they...

A survey reported that 37% of people plan to spend more on eating out after they retire. If

eight people are randomly​ selected, determine the values below.

a.

The expected number of people who plan to spend more on eating out after they retire

b.

The standard deviation of the individuals who plan to spend more on eating out after they retire

c.

The probability that two or fewer in the sample indicate that they actually plan to spend more on eating out after retirement

Solutions

Expert Solution

Solution:

Given:

p = probability of people plan to spend more on eating out after they retire = 0.37

n = sample size = Number of people  randomly​ selected = 8

Part a)

The expected number of people who plan to spend more on eating out after they retire

x = Number of people who plan to spend more on eating out after they retire follows a Binomial distribution with parameters n =8 and p = 0.37

Thus mean or expected value for Binomial distribution is given by:

Thus the expected number of people who plan to spend more on eating out after they retire =

Part b)

The standard deviation of the individuals who plan to spend more on eating out after they retire

Part c)

The probability that two or fewer in the sample indicate that they actually plan to spend more on eating out after retirement

That is find:  

Using Binomial probability formula:

Where

and q = 1- p = 1 - 0.37 = 0.63

Thus

and

Thus

Thus the probability that two or fewer in the sample indicate that they actually plan to spend more on eating out after retirement is 0.3811.


Related Solutions

A survey reported that 3232​% of people plan to spend more on eating out after they...
A survey reported that 3232​% of people plan to spend more on eating out after they retire. If tenten people are randomly​ selected, determine the values below. a. The expected number of people who plan to spend more on eating out after they retire b. The standard deviation of the individuals who plan to spend more on eating out after they retire c. The probability that two or fewer in the sample indicate that they actually plan to spend more...
A survey by KRC Research for U.S. News reported that 40% of people      plan to...
A survey by KRC Research for U.S. News reported that 40% of people      plan to spend more on eating out after they retire. Suppose a random sample of 20         people are selected and the process follows a binomial distribution, with p = 0.40 a. What is the expected value and standard deviation of the people in the sample who       plan to spend more on eating out after they retire. b. What is the probability that 8...
A survey of college students reported that they spend an average of $9.50 a day on...
A survey of college students reported that they spend an average of $9.50 a day on dinner with a standard deviation of $3. What is the probability that 100 randomly selected college students will spend less than $10.00 on average for dinner? Round your answer to 4 decimal places.
The 2011 National Business Ethics Survey defines “active social networkers” as people who spend more than...
The 2011 National Business Ethics Survey defines “active social networkers” as people who spend more than 30 percent of the workday participating on social networking sites. According to the results of the survey, active social networkers air company linen in public. Sixty percent would comment on their personal sites about their company if it was in the news, 53% say they share information about work projects once a week or more, and more than a third say they often comment,...
A travel survey reported that Americans spend a mean of $160 a day with a standard...
A travel survey reported that Americans spend a mean of $160 a day with a standard deviation of 12.25 a day when they sent on vacation. The sample size was 36. Find the 95% confidence interval for the population mean.
A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...
A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 994 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.53 hours with a standard deviation of 0.66 hour. ). A histogram of time spent eating and drinking each day is skewed right. Use this result to explain why a large sample size is needed to construct a confidence interval for the...
A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...
A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1071 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.73 hours with a standard deviation of .51 hour. 1) Determine and interpret a 95% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day. The nutritionist is 95% confident that the mean...
A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...
A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1034 people age 15 or? older, the mean amount of time spent eating or drinking per day is 1.06 hours with a standard deviation of 0.71 hour. Complete parts ?(a) through ?(d) below. ?(a) A histogram of time spent eating and drinking each day is skewed right. Use this result to explain why a large sample size is needed to...
A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...
A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1094 people age 15 or​ older, the mean amount of time `spent eating or drinking per day is 1.48 hours with a standard deviation of 0.69 hour. Complete parts ​(a) through ​(d) below. ​ (a) A histogram of time spent eating and drinking each day is skewed right. Use this result to explain why a large sample size is needed...
A nutritionist wants to determine how much time nationally people spend eating and drinking. The record...
A nutritionist wants to determine how much time nationally people spend eating and drinking. The record shows that the mean was 1.5 hours. Suppose for a random sample of 921 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.62 hours with a standard deviation of 0.71 hour. Does the C.I. suggest a different population mean? No. The sample suggested that the population mean was 1.5 hours. No. The sample suggested that...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT