Write the net ionic equation for each reaction. (Include the states of matter for each reactant...

Write the net ionic equation for each reaction. (Include the states of matter for each reactant and product.)

a. HNO₃(aq) + NaOH(aq)

b. H₂SO₄(aq) + KOH(aq)

Solutions

Expert Solution

we have below given equation

HNO3 (aq) + NaOH (aq) --> NaNO3 (aq) + H2O (l)

Total ionic equation is

Spectator ions should not be removed here. Spectator ions are part of total ionic equation

H+ (aq) + NO3- (aq) + Na+ (aq) + OH- (aq) --> Na+ (aq) + NO3- (aq) + H2O (l)

Spectator ions should be removed now. Spectator ions are not part of total ionic equation

After removing Spectator ions, net ionic equation is:

H+ (aq) + OH- (aq) —> H2O (l)

H⁺ (aq) + OH^- (aq) —> H₂O (l)

we have below given equation

H2SO4 (aq) + 2 KOH (aq) --> K2SO4 (aq) + 2 H2O (l)

Total ionic equation is

Spectator ions should not be removed here. Spectator ions are part of total ionic equation

2 H+ (aq) + SO42- (aq) + 2 K+ (aq) + 2 OH- (aq) --> 2 K+ (aq) + SO42- (aq) + 2 H2O (l)

Spectator ions should be removed now. Spectator ions are not part of total ionic equation

After removing Spectator ions, net ionic equation is:

H+ (aq) + OH- (aq) --> H2O (l)

H⁺ (aq) + OH^- (aq) —> H₂O (l)

queen_honey_blossom answered 1 year ago

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