Question

For the reaction; write the conventional equation, ionic equation, and net ionic equation, when solid copper (II) hydroxide is "dissolved" by hydrochloric acid.

Answer 1

Copper hydroxide which is a pale blue solid usually prepared using the following equation:

CuSO₄+ 2NaOH → Cu (OH) _{2 (ppt)} + Na₂SO₄

Reaction of solid copper (II) hydroxide and hydrochloric acid is an acid-base double replacement reaction because copper hydroxide acts as a weak base and hydrochloric acid is well-known acid. Double replacement reaction is the chemical reaction when two compounds (reactants) react and respective cations and anions of reacting species just switch places to form two new chemical species.

The conventional equation when solid copper hydroxide react with hydrochloric acid will be:
Cu (OH) ₂(s) + 2HCl (aq) → CuCl₂ (aq) + 2H₂O (l)

that is formation of copper chloride will occur.

Ionic equation (in aqueous form; neutralization reaction)

Cu²⁺ + 2 OH^- + 2H⁺ + 2Cl^- → Cu²⁺ + 2Cl^- + 2 OH^- + 2H⁺

In this reaction, no precipitation will occur as copper chloride will remain in the solution form.