Question

Test the claim that for the population of statistics final exams, the mean score is 73 using alternative hypothesis that the mean score is different from 73. Sample statistics include n=25, x¯¯¯=74, and s=11. Use a significance level of α=0.05. (Assume normally distributed population.) The test statistic is equation editorEquation Editor The positive critical value is equation editorEquation Editor The negative critical value is

Answer 1

Solution :

= 73

=74

=11

n = 25

This is the two tailed test .

The null and alternative hypothesis is ,

H0 :    = 73

Ha :     73

Test statistic = z

= ( - ) / / n

= (74-73) / 11 / 25

= 0.455

Test statistic = z = 0.45

The critical value = 1.96 , - 196

P-value =0.6494

= 0.05  

P-value  ≥

0.6494 ≥ 0.05

Fail to reject the null hypothesis .

There is insufficient evidence to suggest that