What is the final pH of a solution made by mixing 100 mL of 0.05 M...

What is the final pH of a solution made by mixing 100 mL of 0.05 M HNO₃, 100mL of 0.15 and 1,800 mL water?

Expert Solution

HNO3 HCl resultant solution

M1 = 0.05M M2 = 0.15M M3 =

V1 = 100ml V2 = 100ml V3 = 100+100 +1800 = 2000ml

M3 = M1V1 + M2V2/V3

= 0.05*100+0.15*100/2000 = 20/2000 = 0.01M

[H^+] = 0.01M

PH = -log[H^+]

= -log0.01 = 2

queen_honey_blossom answered 2 years ago

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