Question

In sheep, an allele for fine wool(F) is dominant over an allele for coarse wool (F). At an independently assorting locus, an allele for black hooves(B) is dominant over an allele for white hooves (b). A ewe that is homozygous for fine wool and black hooves is crossed with a ram that has coarse wool and whites hooves. The offspring are inbred to each other (F1 offspring cross) producing the F2 generation

Answer 1

By using the information in question let's answer

A ewe is homozygous dominant for trait fine wool and black hooves

The genotype will be FFBB and

A Ram his coarse wool and white hooves its also homozygous recessive and genotype is ffbb

Let's cross these two parents together

FFBB x ffbb

F1 is FfBb

It is heterozygous for dominant trait i.e Fine wool and black hooves.

All progeny will have the same genotype and phenotype

By cross F1 itself, we will get

FfBb x FfBb

Their gametes are

FB,Fb,fB, fb.

By using punnet square

The probability of phenotype fine wool and black hooves is 9/16

Their genotype is highlighted in red colour in punnet square.

The probability of course wool and white hooves is 1/16 and their genotype is highlighted in blue i.e. ddww

The sheep with fine wool and white hooves is 3/16 genotype is highlighted in yellow colour in punnet square.

The sheep with coarse wool and black hooves is 3/16 genotype is highlighted in greenish colour in punnet square.

The ratio is 9:3:3:1

9 Fine wool and black hooves

3 Fine wool and white hooves

3 Coarse wool and black hooves

1 coarse wool and white hooves.

Thanks.