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In: Physics

lamda1 = 3.7 uC/cm pic for#1 1) A cylinder of radius a = 6.4 cm and...

lamda₁ = 3.7 uC/cm

lambda 1 = 3.7 uC/cm A cylinder of radius a = 6.4 pic for#1

1) A cylinder of radius a = 6.4 cm and height h = 11.9 cm is aligned with its axis along the y-axis as shown. What is the total flux ? that passes through the cylindrical surface? Enter a positive number if the net flux leaves the cylinder and a negative number if the net flux enters the cylnder.

lambda 1 = 3.7 uC/cm A cylinder of radius a = 6.4 pic for #2

2)Another infinite line of charge with charge density ?₂ = -11.1 ?C/cm parallel to the y-axis is now added at x = 3.05 cm as shown.

What is the new value for E_x(P), the x-component of the electric field at point P?

3)What is the total flux ? that now passes through the cylindrical surface? Enter a positive number if the net flux leaves the cylinder and a negative number if the net flux enters the cylnder.

lambda 1 = 3.7 uC/cm A cylinder of radius a = 6.4 pic for #4

4)The initial infinite line of charge is now moved so that it is parallel to the y-axis at x = -3.05cm.

What is the new value for E_x(P), the x-component of the electric field at point P?

5)What is the total flux ? that now passes through the cylindrical surface? Enter a positive number if the net flux leaves the cylinder and a negative number if the net flux enters the cylnder.

lambda 1 = 3.7 uC/cm A cylinder of radius a = 6.4 cm and height h = 11.9 cm is aligned with its axis along the y-axis as shown. What is the total flux ? that passes through the cylindrical surface? Enter a positive number if the net flux leaves the cylinder and a negative number if the net flux enters the cylnder.

Expert Solution

Flux = charge enclosed

1. flux = lambda1 * h = 44 microCoulomb

3. flux = 11.9*(3.7 - 11.1) = -88 microC

5. flux = 11.9*(3.7 - 11.1) = -88 microC (same as above)

Electric field = lambda/(2Pi*epsilon0*r)

2. E = 9e9 (lambda1/(2r1)+lambda2/(2r2)) = -1.23 megaVolt/m

4. E = 9e9 (lambda1/(2r1)+lambda2/(2r2)) = -1.31 megaVolt/m

genius_generous answered 2 years ago

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