Question

In: Chemistry

An important step in the blood coagulation process is the enzymatic conversion of the protein prothrombin...

An important step in the blood coagulation process is the enzymatic conversion of the protein prothrombin to the lower-molecular-weight clotting agent, thrombin, via cleavage of a portion of the prothrombin polypeptide.

Prothrombin → thrombin + cleaved peptide

The values of s20,w and D20,w for prothrombin have been found to be 4.85S and 4.93×10−11m2s−1 , respectively. The diffusion coefficient for thrombin is 8.76×10−11m2s−1. Assuming that both thrombin and prothrombin are unhydrated spheres with vB=0.70mLg−1, calculate the molecular weight of the cleaved peptide. [Express your answer in units of kg/mol]

Solutions

Expert Solution

Svedberg equation allows one to calculate molar mass of a protein with known sedimentation

coefficient and diffusion coefficient at a given temperature as given below:

M = RTs / D (1- vB)

Calculation of molecular weight of prothrombin:

R = Gas constant = 8.314 J/K/mol

T = Temperature in Kelvin = 298.15 K (assumed Standard temperature: 25oC)

S = sedimentation coefficient = 4.85 S (Svedbergs) = 4.85 X 10-13 (Seconds)

D = diffusion coefficient = 4.93×10−11m2s−1

vB = Partial specific volume = 0.70 mLg−1 = 0.70 cm3g−1

​ = Density = 1.00 gcm-3

Substituting all the values in the above formula one may calculate molecular weight of

prothrombin as shown below:

= 8.314 x 298.15 x 4.85 X 10-13 / 4.93×10−11 (1 – (0.70x1)

= 8.314 x 298.15 x 4.85 X 10-13 / 4.93×10−11 x 0.30

= 8.314 x 298.15 x 4.85 X 10-2 / 4.93 × 0.30

= 8.314 x 298.15 x 0.0485 / 1.479

= 120.22/1.479

= 81.28 Kg mol-1

Molecular weight of prothrombin = = 81.28 Kg mol-1

Calculation of molecular weight of thrombin:

R = Gas constant = 8.314 J/K/mol

T = Temperature in Kelvin = 298.15 K (assumed Standard temperature: 25oC)

S = sedimentation coefficient = 4.85 S (Svedbergs) = 4.85 X 10-13 (Seconds) (assumed same as

that of prothrombin as it’s not given in the data)

D = diffusion coefficient = 8.76×10−11m2s−1

vB = Partial specific volume = 0.70 mLg−1 = 0.70 cm3g−1

= Density = 1.00 gcm-3

Substituting all the values in the above formula one may calculate molecular weight of thrombin as shown below:

= 8.314 x 298.15 x 4.85 X 10-13 / 8.76×10−11 (1 – (0.70x1)

= 8.314 x 298.15 x 4.85 X 10-13 / 8.76×10−11 x 0.30

= 8.314 x 298.15 x 4.85 X 10-2 / 8.76 x 0.30

= 8.314 x 298.15 x 0.0485 / 2.628

= 120.22/2.268

= 45.75 Kg mol-1

Molecular weight of thrombin = 45.75 Kg mol-1

Molecular weight of the cleaved peptide = Molecular weight of prothrombin - Molecular weight

of thrombin

                                                                          = 81.28 - 45.75 = 35.53 Kg mol-1

Molecular weight of the cleaved peptide = 35.53 Kg mol-1


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