In: Chemistry
20. An aqueous solution of nitric acid is standardized by titration with a 0.162 M solution of potassium hydroxide. If 27.1 mL of base are required to neutralize 20.7 mL of the acid, what is the molarity of the nitric acid solution? M nitric acid
KOH(aq) + HNO3(aq) ----------------> KNO3(aq) + H2O(l)
1 mole 1 mole
KOH HNO3
M1 = 0.162M M2 =
V1 = 27.1ml V2 = 20.7ml
n1 = 1 n2 = 1
M1V1/n1 = M2V2/n2
M2 = M1V1n2/n1V2
= 0.162*27.1*1/1*20.7*1 = 0.212M
The molarity of HNO3 is 0.212M