1.) A surface described by the area vector A = + 4.2 i - 4.3 j...

1.) A surface described by the area vector A = + 4.2 i - 4.3 j - 1.8 k is located in a uniform electric field given by E = - 2.0 i - 2.5 j + 4.0 k. Calculate the electric flux through this surface.

2.)An isolated spherical conductor has an excess charge of -13.6 μC placed on its surface. Inside the conductor is a cavity, within which is a point charge of 5.70 μC. How many excess electrons are on the exterior surface of the conductor?

3.)A cubical box has a charge q = 5.9 μC placed at its center. Calculate the electric flux through the right face of the box.

4.)A charged ball with a mass of 18.0 g is suspended on a string in a horizontal electric field of 54.0 N/C directed to the right. The string makes an angle of 11.0 deg to the left of vertical. Find the charge carried by the ball.

Solutions

Expert Solution

1) Electric Flux = E.A

Electric Flux = (- 2.0 i - 2.5 j + 4.0 k).(+ 4.2 i - 4.3 j - 1.8 k).

Electric Flux = -4.2 X2 + 2.5 X 4.3 - 4 X 1.8

Electric Flux = -4.85 Nm²/C

2) The charge inside the cavity will induce the same amount of negative charge on the interior surface and hence the exterior surface will have additional 5.9 uC positive charge.

charge on outer surface Q = -13.6 +5.7 = -7.9 uC

no. of electrons on outer surface n = Q/e = 7.9 X 10^-6/1.6 X 10^-19 = 4.94 X 10¹³

3) Electric flux through the total cube

Since the cube has six faces the flux through right face is

4) Balancing the forces on the ball we get

Dividing the two equations we get

q = 6.35 X 10^-4 C

genius_generous answered 1 year ago

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