In: Statistics and Probability
The following payoff table shows profit for a decision analysis problem with two decision alternatives and three states of nature.
Decision Alternative |
States of Nature | ||
---|---|---|---|
s1 |
s2 |
s3 |
|
d1 |
240 | 90 | 15 |
d2 |
90 | 90 | 65 |
Suppose that the decision maker obtained the probabilities
P(s1) = 0.65, P(s2) = 0.15,
and
P(s3) = 0.20.
Use the expected value approach to determine the optimal decision.
EV(d1) = EV(d2) = The optimal decision is ? d₁ d₂
Decision alternative | s1 | s2 | s3 |
d1 | 240 | 90 | 15 |
d2 | 90 | 90 | 65 |
P(s1)= | 0.65 |
P(s2)= | 0.15 |
P(s3)= | 0.2 |
expected value for decision 1 (d1)=
240*0.65+90*0.15+15*0.2=
172.5
expected value for decision 2 (d2) =
90*0.65+90*0.15+65*0.2=
85
since, E(d1)>E(d2), recommeded decision is
d1
its expected value= 172.5