Question

3.24 LAB C++ : Program: Text message decoder

(1) Use getline() to get a line of user input into a string. Output the line. (3 pts)

Ex:

Enter text:
IDK if I'll go. It's my BFF's birthday. 
You entered: IDK if I'll go. It's my BFF's birthday.

(2) Search the string (using find()) for common abbreviations and print a list of each found abbreviation along with its decoded meaning. (3 pts)

Ex:

Enter text:
IDK if I'll go. It's my BFF's birthday. 
You entered: IDK if I'll go. It's my BFF's birthday. 
BFF: best friend forever
IDK: I don't know

Support these abbreviations:

• BFF -- best friend forever
• IDK -- I don't know
• JK -- just kidding
• TMI -- too much information
• TTYL -- talk to you later

pls help this is so confusing!!

Answer 1

Please find your solution below and if any doubt or need change comment.And do upvote.

CODE:

#include <iostream>
#include<string>
using namespace std;

int main()
{
    string str;
    int index;
    //take input using getline
    cout<<"Enter text:"<<endl;
    getline(cin,str,'\n');
    cout<<"You entered: "<<str<<endl;
    
    //using find() function find if these  string 
    //are present or not 
    index = str.find( "BFF", 0 );
    if( index != string::npos )
    {
       cout<<"BFF: best friend forever\n";
    }
    index = str.find( "IDK", 0 );
    if( index != string::npos )
    {
       cout<<"IDK: I don\'t know\n";
    }
    index = str.find( "JK", 0 );
    if( index != string::npos )
    {
       cout<<"JK: just kidding\n";
    }
    index = str.find( "TMI", 0 );
    if( index != string::npos )
    {
       cout<<"TMI: too much information\n";
    }
    index = str.find( "TTYL", 0 );
    if( index != string::npos )
    {
       cout<<"TTYL: talk to you later\n";
    }

    return 0;
}

OUTPUT: