In: Math
3) In the data from the first problem, one of the scores of a winning team was 131 points. Use what you learned in CH. 3-2, plus the calculated mean and standard deviation, to answer the following question: Is 131 points an unusual score for this group of data? Why or why not? Support your answer by telling me what you did to come to your conclusion. Calculated MEAN (round to the nearest whole number):
FREQUENCY DISTRIBUTION TABLE
CLASSES |
FREQUENCIES f |
75-83 |
4 |
84-92 |
6 |
93-101 |
7 |
102-110 |
7 |
111-119 |
3 |
120-128 |
1 |
129-137 |
2 |
138-146 |
0 |
147-155 |
0 |
CLASSES | FREQUENCIES(f) | Midpoint (x) | f*x |
75-83 | 4 | 79 | 316 |
84-92 | 6 | 88 | 528 |
93-101 | 7 | 97 | 679 |
102-110 | 7 | 106 | 742 |
111-119 | 3 | 115 | 345 |
120-128 | 1 | 124 | 124 |
129-137 | 2 | 133 | 266 |
138-146 | 0 | 142 | 0 |
147-155 | 0 | 151 | 0 |
Mean = SUM(f*x) / SUM(f)
Mean = 3000/30 = 100
CLASSES | FREQUENCIES(f) | Midpoint (x) | f*x | f*(x -Mean)^2 |
75-83 | 4 | 79 | 316 | 1764 |
84-92 | 6 | 88 | 528 | 864 |
93-101 | 7 | 97 | 679 | 63 |
102-110 | 7 | 106 | 742 | 252 |
111-119 | 3 | 115 | 345 | 675 |
120-128 | 1 | 124 | 124 | 576 |
129-137 | 2 | 133 | 266 | 2178 |
138-146 | 0 | 142 | 0 | 0 |
147-155 | 0 | 151 | 0 | 0 |
Considering the Data given is coming from population, then variance
Variance = SUM(f*(x -Mean)^2) / SUM(f) = 6372/30 = 212.4
Standard deviation = = 4.57
Now Mean + 3 * SD = 143.721
Since 131 is lower than (Mean + 3 * SD), it doesn't look unusual. It is within upper control limit.