A current of 17.0 mA is maintained in a single circular loop with a circumference of...

A current of 17.0 mA is maintained in a single circular loop with a circumference of 2.00 m. A magnetic field of 0.800 T is directed parallel to the plane of the loop. (a) Calculate the magnetic moment of the loop. (b) What is the magnitude of the torque exerted on the loop by the magnetic field?

Solutions

Expert Solution

Given that current through the loop is I=17 x 10^-3 A

circumfrence is S=2m

if r is the radius then S=2πr=2m

r=0.318m

strength of the field is B=0.8T

a)the magnetic moment is M=I(πr²)

=5.40 x 10^-3 A m

b) torque parallel to the coil is

τ=MB

=4.32 x 10^-3 N m

genius_generous answered 2 years ago

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