A door is closed under the control of a spring and dashpot. The spring gives a...

A door is closed under the control of a spring and dashpot. The spring gives a torque of 13.5 Nm when the door is closed and has a stiffness of 50 N.m/rad. The dashpot gives a damping torque of 100 N.m.s/rad. The moment of inertia of the door about its hinges is 90 Kg.m2. Derive an expression for the motion of the door if it is opened 90o and released and find approximately the time it takes to close

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samet mamat answered 1 year ago

In a spring-mass-dashpot system, a force of 1 Newtons is required to stretch the spring for...

In a spring-mass-dashpot system, a force of 1 Newtons is required to stretch the spring for .05 meters. A mass of 4 kg is hung from the spring and also attached to a viscous damper that has a damping constant 8 Newton-sec/m. The mass is suddenly set in motion from its equilibrium location at t = 0 by an external force of 8 cost Newtons with initial velocity 0 m/sec. Find the transient solution and the steady state solution of...

Consider a mass-spring-dashpot system with mass 5kg, a spring which is stretched 3 meters by a...

Consider a mass-spring-dashpot system with mass 5kg, a spring which is stretched 3 meters by a force of 10N, and a dashpot which provides a 4N resistance for each m/s of velocity. The mass is also acted on by a periodic force 5 cos(ωt) for some number ω. • For what value of ω (if any) does practical resonance occur? • If the mass starts at rest, at equilibrium, find a formula for x(t) (in terms of ω), the distance...

Consider a mass-spring-dashpot system with mass 5kg, a spring which is stretched 6 meters by a...

Consider a mass-spring-dashpot system with mass 5kg, a spring which is stretched 6 meters by a force of 20N, and a dashpot which provides 4N resistance for each m/s of velocity. The mass is also acted on by a periodic force 5 cos(ωt) for some number ω. For what value of ω (if any) does practical resonance occur? If the mass starts at rest, at equilibrium, find a formula for x(t) in terms of ω, the distance between the mass...

A particle of mass 1 is attached to a spring dashpot mechanism. The stiffness constant of...

A particle of mass 1 is attached to a spring dashpot mechanism. The stiffness constant of the spring is 3 N/m and the drag force exerted on the particle by the dashpot mechanism is 4 times its velocity. At time t=0, the particle is stretched 1/4 m from its equilibrium position. At time t=3 seconds, an impulsive force of very short duration is applied to the system. This force imparts an impulse of 2 N*s to the particle. Find the...

A 1-kg mass stretches a spring 20 cm. The system is attached to a dashpot that...

A 1-kg mass stretches a spring 20 cm. The system is attached to a dashpot that imparts a damping force equal to 14 times the instantaneous velocity of the mass. Find the equation of motion if the mass is released from equilibrium with an upward velocity of 3 m/sec. SOLVE THIS USING MATLAB CODE (SECOND ORDER DIFFERENTIAL EQUATIONS) SOLVE THIS USING MATLAB CODE (SECOND ORDER DIFFERENTIAL EQUATIONS) SOLVE THIS USING MATLAB CODE (SECOND ORDER DIFFERENTIAL EQUATIONS) SOLVE THIS USING MATLAB...

Suppose that the mass in a mass-spring-dashpot system with m = 10, the damping constant c...

Suppose that the mass in a mass-spring-dashpot system with m = 10, the damping constant c = 9, and the spring constant k = 2 is set in motion with x(0) = -1/2 and x'(0) = -1/4. (a) Find the position function x(t). (b) Determine whether the mass passes through its equilibrium position. Sketch the graph of x(t).

A mass-spring-dashpot system is described by my′′ + cy′ + ky = Fo cos ωt, see...

A mass-spring-dashpot system is described by my′′ + cy′ + ky = Fo cos ωt, see §3.6 Eq. (17). This second-order differential equation has been used in simulations, such as this one at the PhET site: https://phet.colorado.edu/en/simulation/legacy/resonance. For m = 2.53kg, c = 0.502N/(m/s), k = 97.2N/m, Fo = 97.2×0.5N = 48.6N,and ω = 2.6, the equation becomes 2.53y′′ + 0.502y′ + 97.2y = 48.6 cos(ωt) ....................... (1) (a) Given the initial value y(0) = 2.20, y′(0) = 0, solve...

A new refrigerator is being designed. Magnets will be used to hold the door closed, and...

A new refrigerator is being designed. Magnets will be used to hold the door closed, and the rubber seal thickness can be selected to adjust the separation between the magnets (and therefore the force). The total length of rubber seal required to go around the door is 6m, and the cost of rubber seal is given equation 2. The pull force when opening the door should be 12N. Determine which of the magnet combinations should be used, and the combined...

What are the different ways of classifying hospitals? Affordable Care Act closed the door on future...

What are the different ways of classifying hospitals? Affordable Care Act closed the door on future physician-owned hospitals effective January 2011 if they want to participate in Medicare. Do you think this is a good restriction? Why or why not?

Describe the energy analysis for both closed and control volume systems.

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