In: Statistics and Probability
Ho : µ1 - µ2 = 10
Ha : µ1-µ2 ╪ 10
Level of Significance , α =
0.05
Sample #1 ----> 1
mean of sample 1, x̅1= 14.750
standard deviation of sample 1, s1 =
17.3500
size of sample 1, n1= 25
Sample #2 ----> 2
mean of sample 2, x̅2= 22.320
standard deviation of sample 2, s2 =
15.2200
size of sample 2, n2= 25
difference in sample means = x̅1-x̅2 =
14.7500 - 22.3 =
-7.57
pooled std dev , Sp= √([(n1 - 1)s1² + (n2 -
1)s2²]/(n1+n2-2)) = 16.3198
std error , SE = Sp*√(1/n1+1/n2) =
4.6159
t-statistic = ((x̅1-x̅2)-µd)/SE = (
-7.5700 - 10 ) /
4.62 = -3.806
Degree of freedom, DF= n1+n2-2 =
48
p-value =
0.0004 (excel function: =T.DIST.2T(t stat,df)
)
Conclusion: p-value <α ,
Reject null hypothesis