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2.70g of Zn (s) reacts with 50.0 mL of 1.00 M HCl solution to produce hydrogen...

2.70g of Zn (s) reacts with 50.0 mL of 1.00 M HCl solution to produce hydrogen gas according to the reaction. (R = 0.08206 L·atm·K-1·mol-

1)

Zn(s) + 2HCl (aq) = ZnCl2 (aq) + H2(g)

a) calculate mole of Zn used in this reaction

b) calculate mole of HCl used in this reaction

c) calculate which reactant is a limiting reactant

d) calculate mole of hydrogen gas formed

e) calculate volume of H2 gas at STP in Liters that will be produced during the reaction

Solutions

Expert Solution

queen_honey_blossom answered 2 years ago
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