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Statistics I – Second Analysis Project You are part of a research team that is interested...

Statistics I – Second Analysis Project

You are part of a research team that is interested in comparing the effectiveness of two different methods for teaching physical science to middle school students. In particular, they wish to compare two individualized computer based instruction programs. One is based on behavioristic principles while the other is based on principles of cognitive theories. A sample of students is randomly selected. Individuals in the sample are then randomly assigned to one of the two instructional programs. After completing the computer-based instruction each student is given the new state physical science test. Although there are many outcomes of potential interest, this study focuses on achievement as measured by the state physical science achievement test.

The research team wishes to estimate the size of the effect and to conduct a statistical test with a set to .05. For this project you should analyze the data and write a short summary of the results. Please turn in (1) the summary, (2) the program, and (3) the output.

Behavioristic Program Participants

Cognitive Program Participants

640

600

560

580

520

440

540

600

450

570

440

470

730

560

610

390

520

500

550

590

500

630

610

490

450

520

580

560

380

400

660

440

410

500

430

570

230

570

450

610

500

510

470

610

320

550

440

430

370

480

520

400

410

500

640

460

530

530

Solutions

Expert Solution

Here we have two independent samples so here we used the two-sample t-test.

Using Minitab statistical software

Hypothesis:

H0: Mean of Behavioristic Program Participants and Cognitive Program Participants are equal

H1: Mean of Behavioristic Program Participants and Cognitive Program Participants are not equal

Test statistic:

Two-Sample T-Test and CI: Behavioristic, cognitive

Two-sample T for Behavioristic vs cognitive

SE
N Mean StDev Mean
Behavioristic 29 537.2 79.1 15
cognitive 29 481.7 96.8 18


Difference = μ (Behavioristic) - μ (cognitive)
Estimate for difference: 55.5
95% CI for difference: (9.0, 102.1)
T-Test of difference = 0 (vs ≠): T-Value = 2.39 P-Value = 0.020 DF = 53

here p value 0.020<0.05 so we reject H0( Null hypothesis) so we say there is statistical difference between two treatments.

conclusion:

The effectiveness of two different methods of Behavioristic Program Participants and Cognitive Program Participants are not equal



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