In: Math
with 90% confidence, for sample mean 375.00 sample standard deviation 12.80 and sample size 35, what is the upper confidence limit with 2 decimal places
SOLUTION:
From given data,
with 90% confidence, for sample mean 375.00 sample standard deviation 12.80 and sample size 35, what is the upper confidence limit with 2 decimal places
Where,
sample mean = = 375.00
standard deviation = = 12.80
sample size = = 35
Degree of freedom = df = n=1 = 35-1 = 34
90% confidence
90% = 90/100 = 0.90
= 1-0.90 = 0.1
Critical value
t,df = t0.10,34 = 1.307
upper confidence limit
+ t,df * (/sqrt(n))
375.00 + 1.307 * (12.80 /sqrt(35))
375.00 + 2.8278
377.8278
Upper confidence limit = 377.83