In: Accounting
The Pullman Mfg., Inc. three-station work cell illustrated in the figure below has two machines at station 1 in parallel. (The product needs to go through only one of the two machines before proceeding to station 2.)
Station 1Machine AStation 1Machine BStation 2Station 320 min/unit20 min/unit12 min/unit3 min/unit
The manager, Ms. Hartley, has asked you to evaluate the system if she adds a parallel machine at station
2.
a) The throughput time of the new work cell is
35
minutes (enter your response as a whole number).
b) The bottleneck time of the new work cell is
10
minutes per unit (enter your response as a whole number).
c) If the firm operates
9
hours per day, 6 days per week, the weekly capacity of the work cell with the second machine at workstation
2
is
324
units (enter your response as a whole number).
d) If the firm operates
9
hours per day, 6 days per week, the weekly capacity of the work cell without the second machine at workstation
2
is
units (enter your response as a whole number
Station 1:Machine A |
||||
20 min/unit |
Station 2 |
Station 3 |
||
Station 1:Machine B |
12 min/unit |
3 min/unit |
||
20 min/unit |
2. The manager, Ms. Hartley, has asked you to evaluate the system if she adds a parallel machine at station
a) The throughput time of the new work cell is 35 minutes (enter your response as a whole number).
Throughput Time = 20Min+12Min+3Min = 35Min
b) The bottleneck time of the new work cell is 10 minutes per unit (enter your response as a whole number).
Bottleneck Time = 20Min/2 = 10Min at station 1
c) If the firm operates 9 hours per day, 6 days per week, the weekly capacity of the work cell with the second machine at workstation 2 is 324 units (enter your response as a whole number).
Weekly capacity = (54hours*60Min/Hr)/10Min per units(Bottleneck time) = 324 Units
d) If the firm operates 9 hours per day, 6 days per week, the weekly capacity of the work cell without the second machine at workstation 2 is units (enter your response as a whole number
Weekly capacity = (54hours*60Min/Hr)/12Min per units(Bottleneck time) = 270 Units