A mixture is prepared using 27.00 mL of a 0.0774 M weak base (pKa = 4.635),...

A mixture is prepared using 27.00 mL of a 0.0774 M weak base (pKa = 4.635), 27.00 mL of a 0.0581 M weak acid (pKa = 3.189) and 1.00 mL of 0.000116 M HIn and then diluting to 100.0 mL, where HIn is the protonated indicator. The absorbance measured at 550 nm in a 5.000 cm cell was 0.1123. The molar absorptivity (ε) values for HIn and its deprotonated form In– at 550 nm are 2.26 × 104 M–1cm–1 and 1.53 × 104 M–1cm–1, respectively. 1.) What is the pH of the solution? 2.)What are the concentrations of In– and HIn? respectively 3.)What is the pKa for HIn?

Expert Solution

queen_honey_blossom answered 1 year ago

A mixture is prepared using 26.00 mL of a 0.0706 M weak base (pKa = 4.591),...

A mixture is prepared using 26.00 mL of a 0.0706 M weak base (pKa = 4.591), 26.00 mL of a 0.0530 M weak acid (pKa = 3.259) and 1.00 mL of 0.000114 M HIn and then diluting to 100.0 mL, where HIn is the protonated indicator. The absorbance measured at 550 nm in a 5.000 cm cell was 0.1227. The molar absorptivity (ε) values for HIn and its deprotonated form In– at 550 nm are 2.26 × 104 M–1cm–1 and...

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