In: Statistics and Probability
The multiple regression model is estimated in Excel and part of the output is provided below.
ANOVA | |||||
df | SS | MS | F | Significance F | |
Regression | 3 | 3.39E+08 | 1.13E+08 | 1.327997 | 0.27152899 |
Residual | 76 | 6.46E+09 | 85052151 | ||
Total | 79 | 6.8E+09 |
Question 8 (1 point)
Use the information from the ANOVA table to complete the following statement.
To test the overall significance of this estimated regression model, the hypotheses would state
there is between attendance and the group of all explanatory variables, jointly.
there is between attendance and the group of all explanatory variables, jointly.
The test statistic is calculated as
/ = ,
which follows an F distribution with numerator and denominator degrees of freedom. Based on the p-value of 0.272, we the null hypothesis at a 5% level of significance, meaning that the relationship between attendance and the collective group of explanatory variables statistically significant.
Word Bank:
85052151is not1.33no significant relationship3.39E+081.13E+0836.46E+09reject767980a significant relationshipfail to rejectis
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ANOVA |
|||||
df |
SS |
MS |
F |
Significance F |
|
Regression |
3 |
3.39E+08 |
1.13E+08 |
1.327997 |
0.27152899 |
Residual |
76 |
6.46E+09 |
85052151 |
||
Total |
79 |
6.8E+09 |
Question: To test the overall significance of this estimated regression model, the hypotheses would state
Answer:
H0: there is no significant relationship between attendance and the group of all explanatory variables, jointly.
H1: there is significant relationship between attendance and the group of all explanatory variables, jointly.
The test statistic is calculated as
F = 1.327997,
which follows an F distribution with 3 numerator and 76 denominator degrees of freedom. Based on the p-value of 0.272, we accept the null hypothesis at a 5% level of significance, meaning that the relationship between attendance and the collective group of explanatory variables is not statistically significant.