Question

In: Chemistry

why must the M-ligand sample solution be free of salt when it is loaded onto the...

why must the M-ligand sample solution be free of salt when it is loaded onto the column?

Solutions

Expert Solution

The M-ligand sample solution contains charge particle (Metal will be in positive charge and ligand will be in negatively charged or neutral containing lone pair). If it contains salt while loading to the column then it will interact with that salt and it will be stuck into the column. Then it will be very difficult to elute it. To avoid, this difficulty M-ligand sample solution must be free of salt when it is loaded onto the column.

Ion exchange chromatography Ion exchange chromatography is based on the charge of the protein you are trying to isolate. If your protein has a high positive charge, you'll want to pass it through a column with a negative charge. The negative charge on the column will bind the positively charged protein, and other proteins will pass through the column. You then use a procedure called "salting out" to release your positively charged protein from the negatively charged column. The column that does this is called a cation exchange column and often uses sulfonated residues. Likewise, you can bind a negatively charged protein to a positively charged column. The column that does this is called an anion exchange column and often uses quaternary ammonium residues.

Salting out will release, or elute, your protein from the column. This technique uses a high salt concentration solution. The salt solution will out-compete the protein in binding to the column. In other words, the column has a higher attraction for the charge of salts than for the charged protein, and it will release the protein in favor of binding the salts instead. Proteins with weaker ionic interactions will elute at a lower salt, so you will often want to elute with a salt gradient. Different proteins elute at different salt concentrations, so you will want to be sure you know well the properties of your protein best results. Also be aware that changes in pH alter the charges in proteins. Be sure you know the isoelectric point of your protein (the isoelectric point is the pH at which the charge of a protein is zero) and make sure the pH of your system is adjusted and buffered accordingly.

The basic steps in using an ion exchange column are:

1. Prepare the column Pour your buffer over the column to make sure it has equilibrated to the required pH.

2. Load your protein solution Some proteins in the solution don't bind and will elute during this loading phase.

3. Salt out Increase the salt concentration to elute the bound proteins. It is best to use a salt gradient to gradually elute proteins with different ionic strengths. At the end bump the system with a very high salt concentration (2-3M) to make sure all proteins are of the column.

4. Remove salts Use dialysis to remove the salts from your protein solution.


Related Solutions

The efficacy of salt-free diets for controlling high blood pressure is studied for a sample of...
The efficacy of salt-free diets for controlling high blood pressure is studied for a sample of 8 patients. Each has their diastolic blood pressure measured before going on the diet and after. The data appear below: Patient 1 2 3 4 5 6 7 8 Sample 1 - Before 93 106 90 93 102 95 88 110 Sample 2 - After 92 102 89 92 101 96 87 105 Assume the differences in blood pressure fit a normal distribution. Use...
If the temperature drops when a salt is dissolved in water. Its heat of solution is...
If the temperature drops when a salt is dissolved in water. Its heat of solution is Select one: a. exothermic b. positive c. cold d. negative
Write the molecular formula of a salt that, when dissolved in water, produces the solution with...
Write the molecular formula of a salt that, when dissolved in water, produces the solution with an basic Ph?
We started with 200.0mL of an 0.08 M Solution of the sodium salt of valine. We...
We started with 200.0mL of an 0.08 M Solution of the sodium salt of valine. We then added 25.0mL of 1.00 M HBr. pka1= 2.286 pka2= 9.719 Ka1= 5.18x10^-3 Ka2= 1.91x10^-10 Please explain the solution and where it is based on the equivalence points! a) What is the new solution made? Be descriptive. b) What is the pH of the new solution?
When a 23.1 mL sample of a 0.427 M aqueous acetic acid solution is titrated with...
When a 23.1 mL sample of a 0.427 M aqueous acetic acid solution is titrated with a 0.415 M aqueous potassium hydroxide solution, (1) What is the pH at the midpoint in the titration? (2) What is the pH at the equivalence point of the titration? (3) What is the pH after 35.7 mL of potassium hydroxide have been added?
A) When a 25.1 mL sample of a 0.434 M aqueous acetic acid solution is titrated...
A) When a 25.1 mL sample of a 0.434 M aqueous acetic acid solution is titrated with a 0.320 M aqueous sodium hydroxide solution, what is the pH after 51.1 mL of sodium hydroxide have been added? pH = B) When a 17.5 mL sample of a 0.492 M aqueous nitrous acid solution is titrated with a 0.451 M aqueous potassium hydroxide solution, what is the pH at the midpoint in the titration? pH =
When a 22.0 mL sample of a 0.448 M aqueous hydrocyanic acid solution is titrated with...
When a 22.0 mL sample of a 0.448 M aqueous hydrocyanic acid solution is titrated with a 0.387 M aqueous barium hydroxide solution, what is the pH after 19.1 mL of barium hydroxide have been added? pH =
When issued a sample of homogenized mixture of sugar and salt, determine the %- composition of...
When issued a sample of homogenized mixture of sugar and salt, determine the %- composition of the mixture by means of conductivity measurements. Describe all necessary steps and pertinent details of the work to be done, including explanation of how obtained data must be analyzed, to determine %-composition of a sucrose/NaCl (sugar/salt) mixture.
Given, 5 100mL flasks each filled with 5.00mL of 0.00139 M ligand solution, 5.00mL of 2M...
Given, 5 100mL flasks each filled with 5.00mL of 0.00139 M ligand solution, 5.00mL of 2M sodium acetate, and 4.00mL of 3M NH_2OH. Then 1.00mL, 2.00mL, 3.00mL, 4.00mL and 5.00mL of 0.255 M Fe2+ is added repectivly to each flask. After that, each flask is filled to the 100mL mark with distilled water. What is the [Fe^2+] after dilution for each flask? given in M. Please show work, thank you.
A 0.40 M solution of a salt NaA has pH=8.95. What is the value of Ka...
A 0.40 M solution of a salt NaA has pH=8.95. What is the value of Ka for the parent acid HA?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT