A 100 g lead ball at a temperature of 100◦C is immersed in 300 g of...

A 100 g lead ball at a temperature of 100◦C is immersed in 300 g of water with the temperature 20◦C contained in an insulated boiler whose heat capacity can be neglected. What will be the mixing temperature? What entropy change does the ball produce? What entropy change does the water bring?What will be the total entropy change?

A 0.10 kg heavy steel ball with a temperature of 200◦C is thrown into a lake with temperatures 20◦C. Which is the entropy change for the ball, for the sea and for the whole system (universe)

Expert Solution

I think there should be the mass of water in the lake should be provided to calculate the mixing temperature, then entropy. Once you know the specific heat for steel ball and water and mass of ball(given) and mass of water in the lake.with the same procedure in above Question we can solve the other part regarding ( a 0.10Kg heavy steel ball).

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genius_generous answered 1 year ago

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