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A gas containing nitrogen, benzene, and toluene is in equilibrium with a liquid mixture of 30.0...

A gas containing nitrogen, benzene, and toluene is in equilibrium with a liquid mixture of 30.0 mole% benzene–70.0 mole% toluene at 50.0°C and 15.0 atm. Estimate the gas-phase composition (mole fractions using Raoult's law).

Solutions

Expert Solution

The vapor pressure of a component of a solution is the product of the mole fraction of the component and the vapor pressure of pure component.

The vapor pressures of pure benzene and pure toluene are not given in the question. However we assume them to be 350 mm Hg and 150 mm Hg respectively.

The mole percent of benzene is 30.0%. Its mole fraction will be . The mole fraction of toluene will be

The vapour pressure of benzene is the product of mole fraction of benzene and vapour pressure of pure benzene. It is mm Hg.

The vapour pressure of toluene is the product of mole fraction of toluene and vapour pressure of pure toluene. It is mm Hg.

The gas phase mole fraction of benzene is the ratio of the vapour pressure of benzene to total pressure. It is

The gas phase mole fraction of toluene is the ratio of the vapour pressure of benzene to total pressure. It is

The gas phase mole fraction of nitrogen is

queen_honey_blossom answered 1 year ago
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