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A liquid is a mixture of benzene (C6H6) and toluene (C7H8). The sample contains 20.309 grams...

A liquid is a mixture of benzene (C6H6) and toluene (C7H8). The sample contains 20.309 grams of benzene and 114.254 grams of toluene. At a given temperature, pure benzene has a vapor pressure of 38.50 torr, while pure toluene has a vapor pressure of 8.99 torr. What is the total combined vapor pressure of the two liquids (in torr)?

Solutions

Expert Solution

moles of benzene = 20.309 / 78 = 0.26

moles of toluene = 114.254 / 92 = 1.242

total moles = 1.242 + 0.26 = 1.5

mole fraction of benzene = XB = 0.26 / 1.5 = 0.172

mole fraction of toulene = XT = 1.242 / 1.5 = 0.828

vapour pressure of total mixture = XB . VB + XT . VT

                                                       = 0.172 x 38.50 + 0.828 x 8.99

                                                       = 14.07 torr

vapour pressure of total mixture   = 14.07 torr

queen_honey_blossom answered 2 years ago
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