prove p(aUbUc)= p(a}+P(b)+p(c)-p{ab)-p(ac)+p(abc)

prove

p(aUbUc)= p(a}+P(b)+p(c)-p{ab)-p(ac)+p(abc)

Expert Solution

milcah answered 1 year ago

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Prove the following using the properties of regular expressions: (ab)* + c + c* = Λ + ab + (ab)* + c(Λ + c*) Λ+ab+abab+ababab(ab)* = Λ + ∅* + (ab)* a(b+c*) + (d+e)* = ab + ac*c* + d + e + (d+e)* a*b + a*a*bc* + d* + ab = d* + ab + a*bc* + Λ a(b+cd*) = a(b+c) + acdd* (a+b)* = ∧* + ∅* + (a*b*)* (ab)*(c*+d*) = (ab)*(c+c*) + (ab)*( ∧ + d*)

Question

prove p(aUbUc)= p(a}+P(b)+p(c)-p{ab)-p(ac)+p(abc)

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Expert Solution

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