Question

In: Statistics and Probability

DT: Donor's Blood Type O- O+ A- A+ B- B+ AB- AB+ P(RT) RT:Receiver's Blood Type...

DT: Donor's Blood Type
O- O+ A- A+ B- B+ AB- AB+ P(RT)
RT:Receiver's Blood Type O- 1 0 0 0 0 0 0 0 7.0%
O+ 1 1 0 0 0 0 0 0 37.0%
A- 1 0 1 0 0 0 0 0 6.0%
A+ 1 1 1 1 0 0 0 0 36.0%
B- 1 0 0 0 1 0 0 0 2.0%
B+ 1 1 0 0 1 1 0 0 8.0%
AB- 1 0 1 0 1 0 1 0 1.0%
AB+ 1 1 1 1 1 1 1 1 3.0%
P(DT) 7.0% 37.0% 6.0% 36.0% 2.0% 8.0% 1.0% 3.0% 100.0%

Table of Probability of Successful Donation Given DT and RT: P(D|DT,RT)

Each person has a blood type (O-,O+,A-,A+,B-,B+,AB-,AB+). The table above shows the probability of a successful blood transfusion given the donor's blood type (DT) and the receiver's blood type (RT). A "1" in this table means that the blood transfusion from DT to RT would be successful. Conversely, a "0" means that a transfusion from DT to RT would be unsuccessful, meaning that the receiver would die if such a transfusion took place. As you can see, O- donors can give to anyone. Conversely, AB+ receivers can receive blood from anyone.

P(DT) is the probability that a randomly selected donor would have a particular blood type. Likewise, P(RT) is the probability that a randomly selected receiver would have a particular blood type.

(a) What is the probability that a randomly selected donor and receiver would have a successful blood transfusion? (The answer is NOT 27/64)

(b) Suppose someone with an unknown blood type needs a transfusion. While their blood type is unknown, we do know that they underwent a successful blood transfusion from an O+ donor in the past. We have obtained an A- donor. What is the probability that the transfusion would be successful from this donor? (The answer is NOT 25% or 50%)

Solutions

Expert Solution

a.) Answer = 0.5617

P(DT,RT) = P(DT) * P(RT)

This gives us the probability table. Multiplying the probability table with the incidence table i.e. the table of 1 or 0 we will get the probability of successful transfusion which will sum of the probabilities in the table.

b.) As transfusion from an O+ donor was successful, the receiver will be one of the following (O+, A+, B+, AB+).

Now for an A- donor transfusion will be successful if the receiver is A+ or AB+. So probability of successful transfusion will be =(P(A+) + P(AB+)) \ (P(A+) + P(AB+) + P(O+) + P(B+))

= 0.4643


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