In: Statistics and Probability
DT: Donor's Blood Type | ||||||||||||||
O- | O+ | A- | A+ | B- | B+ | AB- | AB+ | P(RT) | ||||||
RT:Receiver's Blood Type | O- | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 7.0% | ||||
O+ | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 37.0% | |||||
A- | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 6.0% | |||||
A+ | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 36.0% | |||||
B- | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 2.0% | |||||
B+ | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 8.0% | |||||
AB- | 1 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | 1.0% | |||||
AB+ | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 3.0% | |||||
P(DT) | 7.0% | 37.0% | 6.0% | 36.0% | 2.0% | 8.0% | 1.0% | 3.0% | 100.0% | |||||
Table of Probability of Successful Donation Given DT and RT: P(D|DT,RT)
Each person has a blood type (O-,O+,A-,A+,B-,B+,AB-,AB+). The table above shows the probability of a successful blood transfusion given the donor's blood type (DT) and the receiver's blood type (RT). A "1" in this table means that the blood transfusion from DT to RT would be successful. Conversely, a "0" means that a transfusion from DT to RT would be unsuccessful, meaning that the receiver would die if such a transfusion took place. As you can see, O- donors can give to anyone. Conversely, AB+ receivers can receive blood from anyone.
P(DT) is the probability that a randomly selected donor would have a particular blood type. Likewise, P(RT) is the probability that a randomly selected receiver would have a particular blood type.
(a) What is the probability that a randomly selected donor and receiver would have a successful blood transfusion? (The answer is NOT 27/64)
(b) Suppose someone with an unknown blood type needs a transfusion. While their blood type is unknown, we do know that they underwent a successful blood transfusion from an O+ donor in the past. We have obtained an A- donor. What is the probability that the transfusion would be successful from this donor? (The answer is NOT 25% or 50%)
a.) Answer = 0.5617
P(DT,RT) = P(DT) * P(RT)
This gives us the probability table. Multiplying the probability table with the incidence table i.e. the table of 1 or 0 we will get the probability of successful transfusion which will sum of the probabilities in the table.
b.) As transfusion from an O+ donor was successful, the receiver will be one of the following (O+, A+, B+, AB+).
Now for an A- donor transfusion will be successful if the receiver is A+ or AB+. So probability of successful transfusion will be =(P(A+) + P(AB+)) \ (P(A+) + P(AB+) + P(O+) + P(B+))
= 0.4643