Question

In: Statistics and Probability

Suppose a study of n=269 students was conducted asking their weeknight study time. The mean response...

Suppose a study of n=269 students was conducted asking their weeknight study time. The mean response was 137 min. with an assumed KNOWN standard deviation of 65 min. The hypothesis of interest is whether the mean study time is GREATER than 120 min.

What is the value of the test statistic?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

|

|

Suppose a study of n=269 students was conducted asking their weeknight study time. The mean response was 137 min. with an assumed KNOWN standard deviation of 65 min. The hypothesis of interest is whether the mean study time is GREATER than 120 min.

What is CRITICAL VALUE at alpha=0.01??

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

|

|

Suppose a study of n=269 students was conducted asking their weeknight study time. The mean response was 137 min. with an assumed KNOWN standard deviation of 65 min. The hypothesis of interest is whether the mean study time is GREATER than 120 min.

What is the decision with alpha=0.01?

Note: Enter 3 CAPITAL LETTERS:

REJ - Reject H0

FTR - Fail to Reject H0

CBD - Cannot Be Determined

|

|

Suppose a study of n=269 students was conducted asking their weeknight study time. The mean response was 137 min. with an assumed KNOWN standard deviation of 65 min. The NEW hypothesis of interest is whether the mean study time NOT EQUAL TO 130 min.

What is the test statistic?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

Solutions

Expert Solution

orchestra answered 2 years ago
Next > < Previous

Related Solutions

A survey of 269 students obtaining their study times found a mean of 137 min. with...
A survey of 269 students obtaining their study times found a mean of 137 min. with an assumed standard deviation of 45 min. What is a 99% confidence interval for the population mean? Question 7 options: (131.6, 142.4) (126.8, 147.2) No answer is correct. (132.5, 141.5) (129.9, 144.1)
The Humber Student Federation conducted a survey to determine the mean study time/week of students at...
The Humber Student Federation conducted a survey to determine the mean study time/week of students at the Lakeshore Campus. A sample of 18 students had a mean of 7.5 hours and a standard deviation of 2.2 hours. Assuming that the sampling distribution is about normal, calculate a 99% confidence interval for the mean study time all students at the Lakeshore Campus.
A study is conducted to look at the time students exercise in average. In a random...
A study is conducted to look at the time students exercise in average. In a random sample of 115 students, a researcher finds that the mean time students exercise is 11.3hrs/month with a standard deviation of 6.43hrs/month. Using the Critical Value Methodand a 5% significance level, can a researcher conclude that in average students exercise less than 15 hours per month?
Assume a study of sample size n was conducted and the sample mean was found to...
Assume a study of sample size n was conducted and the sample mean was found to be  and the sample variance s2. Which of the below is the correct way to calculate the standard error of the mean of the sample? Suppose you found the prices for 11 recently sold puppies in your area and recorded them in the table below. The next few questions will use this sample. Price ($): 1437.78 1902.35 1657.76 2057.27 1823.35 1816.12 1808.84 1654.00 1815.81 1968.85...
Suppose a study determines that the amount of time that college students on a given campus...
Suppose a study determines that the amount of time that college students on a given campus work out each week changes from university to university. You are intrigued by this and randomly interview 60 BU students. You find that the average weekly gym time is 3 hours, and the standard deviation is 1 hour. i. Is the sample mean normally distributed? Why or why not?   ii. Your friend thinks the average gym time for Boston University students is equal to...
A survey was conducted two years ago asking college students their top motivations for using a...
A survey was conducted two years ago asking college students their top motivations for using a credit card. To determine whether this distribution has​changed, you randomly select 425 college students and ask each one what the top motivation is for using a credit card. Can you conclude that there has been a change in the claimed or expected​ distribution? Use alpha equals 0.10 .α=0.10. Complete parts​ (a) through​ (d). Response Old Survey​% New Survey ​Frequency, f Rewards 2929​% 112112 Low...
A survey was conducted two years ago asking college students their top motivations for using a...
A survey was conducted two years ago asking college students their top motivations for using a credit card. The percentages are shown in the table to the right. Also shown in the table is the observed frequency for these motivations from a current random sample of college students who use a credit card. Complete parts a through c below. Response Old Survey​ % New Survey ​ Frequency, f Rewards 28​% 110 Low rates 23​% 98 Cash back 21​% 108 Discounts...
A national survey conducted in 2005 on Canadian undergraduate students with a questioner asking them whether...
A national survey conducted in 2005 on Canadian undergraduate students with a questioner asking them whether they do part-time jobs. 1250 students participated in the survey and 802 students said they do part-time jobs. In 2020, researcher claims that there is an increase in undergraduate students doing part-time jobs due to increase in tuition fees. In January 2020, he found 963 students out of randomly selected 1420 students do part-time jobs. Do a hypothesis test at 7% significance level to...
. Suppose that a publisher conducted a survey asking adult consumers the number of fiction paperback...
. Suppose that a publisher conducted a survey asking adult consumers the number of fiction paperback books they had purchased in the previous month. The results are summarized in the Table 2.83. # of books Freq. Rel. Freq. 0 18 1 24 2 24 3 22 4 15 5 10 7 5 9 1 Table 2.83 Are there any outliers in the data? Use an appropriate numerical test involving the IQR to identify outliers, if any, and clearly state your...
An observational study of a group of students was conducted, and students were classified in two...
An observational study of a group of students was conducted, and students were classified in two ways. First, they were each classified as to whether or not they were FullTime or PartTime. Second, they were each classified as to which of two colleges they were in, COS (college of sciences) or CBA (college of business administration). From that data, the following partial joint probability table was constructed. FullTime PartTime COS 7/23 3/23 ? CBA 8/23 ? 13/23 15/23 8/23 1...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT