In: Statistics and Probability
A survey was conducted two years ago asking college students their top motivations for using a credit card. The percentages are shown in the table to the right. Also shown in the table is the observed frequency for these motivations from a current random sample of college students who use a credit card. Complete parts a through c below. |
Response |
Old Survey % |
New Survey Frequency, f |
|
---|---|---|---|---|
Rewards |
28% |
110 |
||
Low rates |
23% |
98 |
||
Cash back |
21% |
108 |
||
Discounts |
77% |
46 |
||
Other |
21% |
63 |
a. Using
α=0.025,
perform a chi-square test to determine if the probability distribution for the motivations for using a credit card changed between the two surveys.What is the null hypothesis, H0?
A.The distribution of motivations is 28% rewards, 23% low rates,21% cash back, 7%discounts, and 21% other.
B.
The distribution of motivations differs from the claimed or expected distribution.
C.The distribution of motivations is
110 rewards,98 low rates,108cash back,46 discounts, and 63 other.
D.
The distribution of motivations follows the normal distribution.
What is the alternate hypothesis, H1?
A.
The distribution of motivations is the same as the claimed or expected distribution.
B.
The distribution of motivations differs from the claimed or expected distribution.
C.
The distribution of motivations is 20% rewards, 20% low rates, 20% cash back, 20% discounts, and 20% other.
D.
The distribution of motivations does not follow the normal distribution.
Calculate the test statistic.
χ2=
(Round to two decimal places as needed.)
Determine the critical value,
χ2α= _____and the rejection region.
(Round to three decimal places as needed.)
Choose the correct rejection region below.
A.
χ2>χ2α
B.
χ2<χ2α
C.
χ2≥χ2α
D.
χ≤χ2α
b. Determine the p-value and interpret its meaning.
p-value=____
(Round to three decimal places as needed.)
Interpret the p-value.
The p-value is the probability of observing a test statistic equal to/greater than/less than
the test statistic, assuming
▼
the distribution of the variable differs from the normal distribution./at least one expected frequency differs from 5./the distribution of the variable is the same as the given distribution./the distribution of the variable differs from the given distribution./the distribution of the variable is the normal distribution./the expected frequencies are all equal to 5.
c. What conclusion can be drawn about the motivation behind the use of a credit card by college students between the two surveys?
▼
Reject
Do not reject
Upper H 0H0.
At the
2.52.5%
significance level, there
▼
is not
is
enough evidence to conclude that the distribution of motivations
▼
is the same as
differs from
the claimed or expected distribution.
Click to select your answer(s).
a)NUll hypothesis HO:
A.The distribution of motivations is 28% rewards, 23% low rates,21% cash back, 7%discounts, and 21% other.
alternate hypothesis, H1 :
B: The distribution of motivations differs from the claimed or expected distribution
applying chi square goodness of fit test: |
relative | observed | Expected | Chi square | ||
Category | frequency(p) | Oi | Ei=total*p | R2i=(Oi-Ei)2/Ei | |
1 | 0.2800 | 110 | 119.00 | 0.6807 | |
2 | 0.2300 | 98 | 97.75 | 0.0006 | |
3 | 0.2100 | 108 | 89.25 | 3.9391 | |
4 | 0.0700 | 46 | 29.75 | 8.8761 | |
5 | 0.2100 | 63 | 89.25 | 7.7206 | |
total | 1.00 | 425 | 425 | 21.2170 | |
test statistic X2= | 21.22 |
degree of freedom =categories-1= | 4 | |||
for 0.025 level and 4 df :crtiical value X2 = | 11.143 | from excel: chiinv(0.025,4) |
e correct rejection region : C .χ2≥χ2α
The p-value is the probability of observing a test statistic greater than the test statistic, assuming the distribution of the variable is the same as the given distribution
c)
Reject HO At the 2.5 % significance level, there is enough evidence to conclude that the distribution of motivations differs from the claimed or expected distribution.