Let X represent the standard normal random variable. The P{X > 2.07} is equal to:

Expert Solution

P(X > 2.07) = P(Z > 2.07) = 1 - P(Z < 2.07) = 1 - 0.9808 = 0.0192 (ans)

milcah answered 9 months ago

Find the following probabilities for the standard normal random variable z z : a) P(−2.07≤z≤1.93)= P...

Find the following probabilities for the standard normal random variable z z : a) P(−2.07≤z≤1.93)= P ( − 2.07 ≤ z ≤ 1.93 ) = (b) P(−0.46≤z≤1.73)= P ( − 0.46 ≤ z ≤ 1.73 ) = (c) P(z≤1.44)= P ( z ≤ 1.44 ) = (d) P(z>−1.57)= P ( z > − 1.57 ) =

Let z be a random variable with a standard normal distribution. Find “a” such that P(|Z|...

Let z be a random variable with a standard normal distribution. Find “a” such that P(|Z| <A)= 0.95 This is what I have: P(-A<Z<A) = 0.95 -A = -1.96 How do I use the symmetric property of normal distribution to make A = 1.96? My answer at the moment is P(|z|< (-1.96) = 0.95

Let X represent a binomial random variable with n = 110 and p = 0.19. Find...

Let X represent a binomial random variable with n = 110 and p = 0.19. Find the following probabilities. (Do not round intermediate calculations. Round your final answers to 4 decimal places.) a. P(X ≤ 20) b. P(X = 10) c. P(X > 30) d. P(X ≥ 25)

Let X represent a binomial random variable with n = 180 and p = 0.23. Find...

Let X represent a binomial random variable with n = 180 and p = 0.23. Find the following probabilities. (Do not round intermediate calculations. Round your final answers to 4 decimal places.) a. P(X less than or equal to 45) b. P(X=35) c. P(X>55) d. P (X greater than or equal to 50)

Let Z be a standard normal variable. calculate the following; P(Z less than or equal to...

Let Z be a standard normal variable. calculate the following; P(Z less than or equal to 1.29) = P(-0.76 < Z< 1.92)=

Let z be a random variable with a standard normal distribution. Find P(0 ≤ z ≤...

Let z be a random variable with a standard normal distribution. Find P(0 ≤ z ≤ 0.46), and shade the corresponding area under the standard normal curve. (Use 4 decimal places.)

1) Let X be a normally distributed random variable with a standard deviation equal 3

1) Let X be a normally distributed random variable with a standard deviation equal 3; i.e. X∼N(μ, σ=3. Someone claims that μ=13. A random sample of 16 observations generate a sample mean of 14.56. a) Does the sample mean provide evidence against the above claim at 5% significance level? Complete the four steps of the test of hypothesis: b) Assume that X was not normal; for example, X∼Unifμ-3, μ+3 which would have the same standard deviation. Use simulation to...

1. (Use Computer) Let X represent a binomial random variable with n = 400 and p...

1. (Use Computer) Let X represent a binomial random variable with n = 400 and p = 0.8. Find the following probabilities. (Round your final answers to 4 decimal places.) Probability a. P(X ≤ 330) b. P(X > 340) c. P(335 ≤ X ≤ 345) d. P(X = 300) 2. (Use computer) Suppose 38% of recent college graduates plan on pursuing a graduate degree. Twenty three recent college graduates are randomly selected. a. What is the...

Let X be a standard normal random variable so that X N(0; 1). For this problem...

Let X be a standard normal random variable so that X N(0; 1). For this problem you may want to refer to the table provided on Canvas. Recall, that (x) denotes the standard normal CDF. (a) Find (1:45). (b) Find x, such that (x) = 0:4. (c) Based on the fact that (1:645) = 0:95 nd an interval in which X will fall with 95% probability. (d) Find another interval (dierent from the one in (c)) into which X will...

Let x be a normal random variable with mean 35 and standard deviation 2. a. Find...

Let x be a normal random variable with mean 35 and standard deviation 2. a. Find P(30 < x < 38). .9270 b. Find P(x > 34). .6915 c. Find P(x = 36). 0 d. Find the area under the distribution of x to the left of 31. .0228

Question