Let z be a random variable with a standard normal
distribution.
Find “a” such that P(|Z| <A)= 0.95
This is what I have:
P(-A<Z<A) = 0.95
-A = -1.96
How do I use the symmetric property of normal distribution to make
A = 1.96?
My answer at the moment is P(|z|< (-1.96) = 0.95
Let z be a random variable with a standard normal distribution.
Find P(0 ≤ z ≤ 0.46), and shade the corresponding area under the
standard normal curve. (Use 4 decimal places.)
1- Let Z be a standard normal random variable and
calculate the following probabilities, drawing pictures wherever
appropriate. (Round your answers to four decimal places.)
(e)
P(Z ≤ 1.08)
(f)
P(−1.25 ≤ Z)
(h)
P(1.08 ≤ Z ≤ 2.50)
(j)
P(|Z| ≤ 2.50)
2- In each case, determine the value of the constant c
that makes the probability statement correct. (Round your answers
to two decimal places.)
(a) P(Z < c) = 0.9834
(b) P(0 ≤ Z ≤ c)
= 0.3078
(d) P(−c...
Let Z be a standard normal random variable and calculate the
following probabilities, drawing pictures wherever appropriate.
(Round your answers to four decimal places.)
(a) P(0 ≤ Z ≤ 2.33)
0.4875
Incorrect: Your answer is incorrect.
(b) P(0 ≤ Z ≤ 2)
0.4772
Correct: Your answer is correct.
(c)
P(−2.70 ≤ Z ≤ 0)
0.4981
Incorrect: Your answer is incorrect.
(d)
P(−2.70 ≤ Z ≤ 2.70)
0.9963
Incorrect: Your answer is incorrect.
(e) P(Z ≤ 1.93)
0.9545
Incorrect: Your answer...
Let Z be a standard normal random variable and
calculate the following probabilities, drawing pictures wherever
appropriate. (Round your answers to four decimal places.)
(a)
P(0 ≤ Z ≤ 2.09)
(b)
P(0 ≤ Z ≤ 2)
(c)
P(−2.10 ≤ Z ≤ 0)
(d)
P(−2.10 ≤ Z ≤ 2.10)
(e)
P(Z ≤ 1.62)
(f)
P(−1.05 ≤ Z)
(g)
P(−1.10 ≤ Z ≤ 2.00)
(h)
P(1.62 ≤ Z ≤ 2.50)
(i)
P(1.10 ≤ Z)
(j)
P(|Z| ≤ 2.50)
You may need to...
Let Z be a standard normal random variable and
calculate the following probabilities, drawing pictures wherever
appropriate. (Round your answers to four decimal places.)
(a) P(0 ≤ Z ≤
2.97)
(b) P(0 ≤ Z ≤ 2)
(c) P(−2.50 ≤
Z ≤ 0)
(d) P(−2.50 ≤
Z ≤ 2.50)
(e) P(Z ≤ 1.03)
(f) P(−1.75 ≤
Z)
(g) P(−1.50 ≤
Z ≤ 2.00)
(h) P(1.03 ≤ Z ≤
2.50)
(i) P(1.50 ≤ Z)
(j) P(|Z| ≤ 2.50)
Let Z be a standard normal random variable and
calculate the following probabilities, drawing pictures wherever
appropriate. (Round your answers to four decimal places.)
(a) P(0 ≤ Z ≤ 2.72)
(b) P(0 ≤ Z ≤ 1)
(c) P(−2.90 ≤ Z ≤ 0)
(d) P(−2.90 ≤
Z ≤ 2.90)
(e) P(Z ≤ 1.37)
(f) P(−1.55 ≤
Z)
(g) P(−1.90 ≤
Z ≤ 2.00)
(h) P(1.37 ≤ Z ≤
2.50)
(i) P(1.90 ≤ Z)
(j) P(|Z| ≤ 2.50)
You may need to use the appropriate table in the Appendix of
Tables to...
Let
Z
be a standard normal random variable. Calculate the following
probabilities using the calculator provided. Round your responses
to at least three decimal places.
=P≤Z−1.63
=P>Z0.71
=P<−0.93<Z2.09
Let Z be a standard normal random variable and calculate the
following probabilities, drawing pictures wherever appropriate.
(Round your answers to four decimal places.)
(a) P(0 ≤ Z ≤ 2.63)
(b) P(0 ≤ Z ≤ 2)
(c) P(−2.60 ≤ Z ≤ 0)
(d) P(−2.60 ≤ Z ≤ 2.60)
(e) P(Z ≤ 1.63)
(f) P(−1.15 ≤ Z)
(g) P(−1.60 ≤ Z ≤ 2.00)
(h) P(1.63 ≤ Z ≤ 2.50)
(i) P(1.60 ≤ Z)
(j) P(|Z| ≤ 2.50)
You may need to...
Let Z be a standard normal random variable and calculate the
following probabilities, drawing pictures wherever appropriate.
(Round your answers to four decimal places.)
(a) P(0 ≤ Z ≤ 2.56)
(b) P(0 ≤ Z ≤ 2)
(c) P(−2.20 ≤ Z ≤ 0)
(d) P(−2.20 ≤ Z ≤ 2.20)
(e) P(Z ≤ 1.02)
f) P(−1.85 ≤ Z)
(g) P(−1.20 ≤ Z ≤ 2.00)
(h)
P(1.02 ≤ Z ≤ 2.50)
(i) P(1.20 ≤ Z)
(j) P(|Z| ≤ 2.50)