A sample of 73 oversized packages delivered by OOPS (Only Oversized Parcel Service) is randomly selected...

A sample of 73 oversized packages delivered by OOPS (Only Oversized Parcel Service) is randomly selected and weighed, producing an average weight of 61.3 lbs. Assuming that the population standard deviation is known to be 9.2 lbs, find a 95% confidence interval estimate for the average weight of all oversized packages delivered by OOPS.

Solutions

Expert Solution

Solution

Given that,

=61.3

= 9.2

n = 73

A ) At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.960

Margin of error = E = Z/2* ( $\sqrt$ /n)

= 1.960 * (9.2 / $\sqrt$ 73)

= 2.11

At 95% confidence interval estimate of the population mean is,

- E < < + E

61.3 - 2.11 < < 61.3 + 2.11

59.19 < < 63.41

(59.19 , 63.41)

orchestra answered 1 year ago

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