Question
In: Statistics and Probability
Test scores of 9 randomly selected students are: 83, 73, 62, 63, 71, 77, 59, 92,77...
Test scores of 9 randomly selected students are: 83, 73, 62, 63, 71, 77, 59, 92,77 Compute the 99% confident interval of the true mean.
Solutions
Expert Solution
We have for given data,
Sample mean =73
Sample standard deviation =10.69
Sample size =9
Level of significance= 1-0.99=0.01
Degree of freedom =8
t critical value is (by using t table)=3.355
Confidence interval formula is
=(61.05,84.96)
Lower confidence limit=61.05
Upper confidence limit= 84.96
orchestra answered 2 years agoRelated Solutions
The following represent the scores 63 96 71 91 65 62 73 66 85 28 70 &n
The following represent the scores
63 96 71
91 65 62
73 66 85
28 70 82
68 71 77
67 85 53
68 80 82 45
60 42 30
83 45 94
55 56 65
87 96 47
88 51 79 100
92 77 64
83 41 58 77
70 89 78
52 96 77
75 74 77
88 67 47
38 83 81
66 77 61
68 53 88 72
48 77 77 100
53 68 42
60 ...
Height: 62, 67, 62, 63, 67, 74, 63, 73, 63 Weight: 130, 140, 102, 140, 145,...
Height: 62, 67, 62, 63, 67, 74, 63, 73, 63
Weight: 130, 140, 102, 140, 145, 157, 130, 190, 135
2. (CLO 1) Construct a confidence interval to estimate
the mean height and the mean weight by completing the
following:
a. Find the sample mean and the sample standard
deviation of the height.
b. Find the sample mean and the sample standard
deviation of the weight.
c. Construct and interpret a confidence interval to
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The paired data below consist of the test scores of 6 randomly selected students and the...
The paired data below consist of the test scores of 6 randomly
selected students and the number of hours they studied for the
test. Test the claim that there is a linear correlation between
hours of study and test scores, with 0.03 significance level and
P-Value method.
Hours 6 7 5 9 4 10
Score 71 82 58 85 62 91
Math Reading 52 65 63 71 55 61 68 77 66 76 57 70 59 69...
Math
Reading
52
65
63
71
55
61
68
77
66
76
57
70
59
69
76
77
69
76
59
70
74
78
73
80
62
66
59
66
72
76
61
67
55
61
73
77
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