a hydrated form of copper sulfate (cuso4·xh2o) is heated to drive off all the water if...

a hydrated form of copper sulfate (cuso4·xh2o) is heated to drive off all the water if we start with 9.57 g of hydrated salt and have 7.15 of anhydrous CuSo4 after heating find the num. of water molecules associated with each CuSo4 formula unit

Expert Solution

mass of hydrated salt ( CuSO4.xH2O) = 9.57g

mass of anhydrous salt ( CuSO4) = 7.15g

mass of water = mass of hydrated salt ( CuSO4.xH2O) -mass of anhydrous salt ( CuSO4)

= 9.57-7.15 = 2.42g

no of moles of CuSO4 = W/G.M.Wt = 7.15/159.5 = 0.0448moles

no of moles of H2O = W/G.M.Wt = 2.42/18 = 0.1344 moles

divide with lowest no of moles

CuSO4 : H2O = 0.0448 : 0.1344

= 0.0448/0.0448 : 0.1344/0.0448

= 1:3

There fore hydrate salt is CuSO4.3H2O

queen_honey_blossom answered 2 years ago

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