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In: Chemistry

For each of the following unbalance chemical equation suppose that exactly 5.00g of each reactant is...

For each of the following unbalance chemical equation suppose that exactly 5.00g of each reactant is taken. Determine which reactant is limiting and calculate what mass of each product is expected ( assuming that the limiting reactant is completely consumed)
A. S + H2SO4 = SO2 +H2O
B. MnO2 + H2SO4 = Mn(SO4)2 + H2O
C. H2S + O2 = SO2 + H2O
D. AgNO3 + Al = Ag + Al(NO3)3

Solutions

Expert Solution

A. )

S + 2H2SO4 ---------------------> 3SO2 +2H2O

32 g 196 g                                   192g

5 g      5g    

limiting reagent is H2SO4

196 g H2SO4 gives ------------------> 192 g SO2

5g H2SO4 gives = 192 x 5 / 196 = 4.89 g SO2

B.)

MnO2 + 2H2SO4 ----------------------> Mn(SO4)2 + 2H2O

86.9g         196g                                     247g

5g                5g

limilting reagent H2SO4

196 g ------------------> 247 g

5g H2SO5 gives = 247 x 5 / 196 = 6.3 g Mn(SO4)2

C.)

2H2S + 3O2 ---------------------> 2SO2 + 2H2O

68g        96g                               128g

5g          5g                                

limiting reagent O2

96 g O2 --------------> 128 g SO2

5g ----------------> 5 x 128 /96 = 6.67 g SO2

D)

.3 AgNO3 +    Al -------------------> 3 Ag + Al(NO3)3

    510g         27g                              324g

    5g             5g                                  

limiting reagent Al

27g --------------------> 324 g Ag

5g --------------------> 5 x 324 /27 = 60 g Ag

queen_honey_blossom answered 1 year ago
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