Question

In: Statistics and Probability

Let x be a random variable that represents the percentage of successful free throws a professional...

Let x be a random variable that represents the percentage of successful free throws a professional basketball player makes in a season. Let y be a random variable that represents the percentage of successful field goals a professional basketball player makes in a season. A random sample of n = 6 professional basketball players gave the following information.

x 73 74 80 66 77 77
y 50 52 45 46 52 53

Verify that Se ≈ 3.694, a ≈ 38.254, b 0.153, and , ∑x =447, ∑y =298, ∑x2 =33,419, and ∑y2 =14,858, and use a 5% level of significance to find the P-value for the test that claims that β is greater than zero.

Group of answer choices

Since the P-value is less than α = 0.05, we reject the null hypothesis that the population slope β is equal to zero in favor of the alternate hypothesis that the population slope βis greater than zero.

Since the P-value is greater than α = 0.05, we reject the null hypothesis that the population slope β is equal to zero in favor of the alternate hypothesis that the population slope βis greater than zero.

Since the P-value is greater than α = 0.05, we fail to reject the null hypothesis that the population slope β is equal to zero in favor of the alternate hypothesis that the population slope β is greater than zero.

Since the P-value is equal to α = 0.05, we reject the null hypothesis that the population slope β is equal to zero in favor of the alternate hypothesis that the population slope βis greater than zero.

Since the P-value is equal to α = 0.05, we fail to reject the null hypothesis that the population slope β is equal to zero in favor of the alternate hypothesis that the population slope βis greater than zero.

Solutions

Expert Solution

null hypothesis: Ho:               β1 = 0
Alternate Hypothesis: Ha: β1 > 0
0.05 level,right tail test and n-2= df, critical t= 2.132
Decision rule: reject Ho if test statistic t>2.132
estimated std error of slope =se(β1) =s/√Sxx= 0.3408
test stat t = (bo-β1)/se(β1)= = 0.4496
p value: = 0.3382

since p value is rgeater than 0.05:

Since the P-value is greater than α = 0.05, we fail to reject the null hypothesis that the population slope β is equal to zero in favor of the alternate hypothesis that the population slope β is greater than zero.


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