In: Statistics and Probability
Let x be a random variable that represents the percentage of successful free throws a professional basketball player makes in a season. Let y be a random variable that represents the percentage of successful field goals a professional basketball player makes in a season. A random sample of n = 6 professional basketball players gave the following information.
x 67 64 75 86 73 73
y 42 39 48 51 44 51
(a) Verify that Σx = 438, Σy = 275, Σx2 = 32264, Σy2 = 12727, Σxy = 20231, and r ≈ 0.827
(b) Use a 5% level of significance to test the claim that ρ > 0. (Round your answers to two decimal places.)
t
critical t
Conclusion Reject the null hypothesis, there is sufficient evidence that ρ > 0.
Reject the null hypothesis, there is insufficient evidence that ρ > 0.
Fail to reject the null hypothesis, there is insufficient evidence that ρ > 0.
Fail to reject the null hypothesis, there is sufficient evidence that ρ > 0.
(c) Verify that Se ≈ 3.1191, a ≈ 6.564, b ≈ 0.5379, and x ≈ 73.000.
Se
a
b
x bar
(d) Find the predicted percentage y hat of successful field goals for a player with x = 73% successful free throws. (Round your answer to two decimal places.)
% =
(e) Find a 90% confidence interval for y when x = 73. (Round your answers to one decimal place.)
lower limit % =
upper limit % =
(f) Use a 5% level of significance to test the claim that β > 0. (Round your answers to two decimal places.)
t
critical t
Conclusion
Reject the null hypothesis, there is sufficient evidence that β > 0.
Reject the null hypothesis, there is insufficient evidence that β > 0.
Fail to reject the null hypothesis, there is insufficient evidence that β > 0.
Fail to reject the null hypothesis, there is sufficient evidence that β > 0.
(g) Find a 90% confidence interval for β. (Round your answers to three decimal places.)
lower limit
upper limit
Interpret its meaning.
For every percentage increase in successful free throws, the percentage of successful field goals increases by an amount that falls within the confidence interval.
For every percentage increase in successful free throws, the percentage of successful field goals decreases by an amount that falls outside the confidence interval.
For every percentage increase in successful free throws, the percentage of successful field goals decreases by an amount that falls within the confidence interval.
For every percentage increase in successful free throws, the percentage of successful field goals increases by an amount that falls outside the confidence interval.
Thank you in advance!
a)'
ΣX = | 438.000 |
ΣY= | 275.000 |
ΣX2 = | 32264.000 |
ΣY2 = | 12727.000 |
ΣXY = | 20231.000 |
r = | 0.827 |
b)
test statistic t = | r*(√(n-2)/(1-r2))= | 2.94 | ||
t crit = | 2.13 |
Reject the null hypothesis, there is sufficient evidence that ρ > 0
c)
Se =√(SSE/(n-2))= | 3.11910 | |||
a= | 6.564 | |||
b= | 0.5379 | |||
X̅= | 73.0000 |
d)
predicted value = | 45.83 |
e)
std error of confidence interval = | s*√(1+1/n+(x0-x̅)2/Sxx)= | 3.3690 | |||||
for 90 % confidence and 4degree of freedom critical t= | 2.132 | ||||||
lower limit = | 38.7 | ||||||
uppr limit = | 53.0 |
f)
test statistic t = | r*(√(n-2)/(1-r2))= | 2.94 | ||
t crit = | 2.13 |
Reject the null hypothesis, there is sufficient evidence that β > 0.
g)
std error of slope sb1 = | s/√SSx= | 0.1832 | ||||
for 90 % confidence and -2degree of freedom critical t= | 2.1320 | |||||
90% confidence interval =b1 -/+ t*standard error= | (0.147,0.928) | |||||
lower limit = | 0.147 | |||||
uppr limit = | 0.928 |
For every percentage increase in successful free throws, the percentage of successful field goals increases by an amount that falls within the confidence interval.