A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,...

A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 1046 and x = 584 who said "yes." Use a 99% confidence level.

Expert Solution

Level of Significance,   α =    0.01
Number of Items of Interest,   x =   584
Sample Size,   n =    1046

Sample Proportion ,    p̂ = x/n =    0.558
z -value =   Zα/2 =    2.576   [excel formula =NORMSINV(α/2)]

Standard Error ,    SE = √[p̂(1-p̂)/n] =    0.0154
margin of error , E = Z*SE =    2.576   *   0.0154   =   0.0396

99%   Confidence Interval is
Interval Lower Limit = p̂ - E =    0.558   -   0.0396   =   0.5188
Interval Upper Limit = p̂ + E =   0.558   +   0.0396   =   0.5979

99%   confidence interval is (   0.5188   < p <    0.5979   )

Please revert in case of any doubt.

Please upvote. Thanks in advance

orchestra answered 2 years ago

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A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,...

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