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y''+2y'+2y=0,y(45)=2,y'(45)=-2
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y''+2y'+2y=0,y(45)=2,y'(45)=-2
y''+2y'+2y=0,y(45)=2,y'(45)=-2
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Question : y''=4y'+8y=0 , (y''-4y'+13y)^2=0 , (y''+2y'+2y)^2=0 , y''-6y'+13y=0,y(0)=3 , y'(0)=13 , 2y''-6y'+17y=0,y(0)=2, y'(0)=13
solve using undetermined coefficients. y''' + 2y'' -y'-2y= 24e^-3t + 48t^2; y(0)=y'(0)=y''(0)=0
solve using undetermined coefficients. y''' + 2y'' -y'-2y= 24e^-3t + 48t^2; y(0)=y'(0)=y''(0)=0
Use the Laplace transform to solve the problem with initial values y''+2y'-2y=0 y(0)=2 y'(0)=0
Use the Laplace transform to solve the problem with initial values y''+2y'-2y=0 y(0)=2 y'(0)=0
y''' + 2y'' − y' − 2y = sin(4t), y(0) = 0, y'(0) = 0, y''(0) = 1
y''' + 2y'' − y' − 2y = sin(4t), y(0) = 0, y'(0) = 0, y''(0) = 1
Laplace Question : y''-3y'+2y=4cos2t,y(0)=-2,y'(0)=0
Laplace Question : y''-3y'+2y=4cos2t,y(0)=-2,y'(0)=0
Given the differential equation y''+y'+2y=0, y(0)=−1, y'(0)=2y′′+y′+2y=0, y(0)=-1, y′(0)=2 Apply the Laplace Transform and solve for Y(s)=L{y}Y(s)=L{y}. You do not...
Given the differential equation y''+y'+2y=0, y(0)=−1, y'(0)=2y′′+y′+2y=0, y(0)=-1, y′(0)=2 Apply the Laplace Transform and solve for Y(s)=L{y}Y(s)=L{y}. You do not need to actually find the solution to the differential equation.
Solve the initial value problem: y''+2y'+y = x^2 , y(0)=0 , y'(0) = 0
Solve the initial value problem: y''+2y'+y = x^2 , y(0)=0 , y'(0) = 0
y''-y'-2y=0 y(0)=0 y'(0)=2 laplace dönüşümü kullanarak değer problemini çözünüz
y''-y'-2y=0 y(0)=0 y'(0)=2 laplace dönüşümü kullanarak değer problemini çözünüz
y"-3y'+2y=4t-8 , y(0)=2 , y'(0)=7 y(t)=?
y"-3y'+2y=4t-8 , y(0)=2 , y'(0)=7 y(t)=?
Solve the differential equation y''+y'-2y=3, y(0)=2, y'(0) = -1
Solve the differential equation y''+y'-2y=3, y(0)=2, y'(0) = -1
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