Question

In: Physics

You are given a vector in the xy plane that has a magnitude of 82.0 units...

You are given a vector in the xy plane that has a magnitude of 82.0 units and a y component of -58.0 units.
Part A
What are the two possibilities for its x component?
Enter your answers using three significant figures separated by a comma.
Part B
Assuming the x component is known to be positive, specify the magnitude of the vector which, if you add it to the original one, would give a resultant vector that is 80.0 units long and points entirely in the −x direction.
Part C
Specify the direction of the vector.
Express your answer using three significant figures.

Solutions

Expert Solution

Part A..

Let, Given vector = R = Rx i + Ry j

here, |R| = 82.0 units

Ry = -58.0

So,

|R|^2 = Rx^2 + Ry^2

Rx^2 = 82.0^2 - (-58.0)^2 = 3360

Rx = sqrt(3360) = 57.97

Rx = 58.0 unit

Rx = -58.0, +58.0

Part-B.

Given, x-component is known to be positive.

then, R = 58.0 i - 58.0 j

Let, anothe vector is,

R' = R'x i + R'y j

given,

R + R' = -80 i + 0 j

So,

(58.0 i - 58.0 j) + (R'x i + R'y j) = -80 i + 0 j

(58.0 + R'x) i + (-58.0 + R'y) j = -80 i + 0 j

equating both side,

58.0 + R'x = -80

R'x = -80.0-58.0 = -138

-58.0 + R'y = 0

R'y = 58.0 j

then,

R' = -138 i + 58.0 j

Magnitude will be:

|R'| = sqrt(138^2 + 58.0^2)

|R'| = 150

Part-C.

direction will be:

= arctan(R'y/R'x)

= arctan(58.0/(-138))

= 22.8 deg

Part A..

Let, Given vector = R = Rx i + Ry j

here, |R| = 82.0 units

Ry = -58.0

So,

|R|^2 = Rx^2 + Ry^2

Rx^2 = 82.0^2 - (-58.0)^2 = 3360

Rx = sqrt(3360) = 57.97

Rx = 58.0 unit

Rx = +58.0, -58.0

Part-B.

Given, x-component is known to be positive.

then, R = 58.0 i - 58.0 j

Let, anothe vector is,

R' = R'x i + R'y j

given,

R + R' = -80 i + 0 j

So,

(58.0 i - 58.0 j) + (R'x i + R'y j) = -80 i + 0 j

(58.0 + R'x) i + (-58.0 + R'y) j = -80 i + 0 j

equating both side,

58.0 + R'x = -80

R'x = -80.0-58.0 = -138

-58.0 + R'y = 0

R'y = 58.0 j

then,

R' = -138 i + 58.0 j

Magnitude will be:

|R'| = sqrt(138^2 + 58.0^2)

|R'| = 150

Part-C.

direction will be:

= arctan(R'y/R'x)

= arctan(58.0/(-138))

= -22.8 deg above -x axis.

"Let me know if you have any query."

"Let me know if you have any query."


Related Solutions

You are given a vector in the xy plane that has a magnitude of 89.0 units...
You are given a vector in the xy plane that has a magnitude of 89.0 units and a y component of -60.0 units. What are the two possibilities for its x component? Assuming the x component is known to be positive, specify the magnitude of the vector which, if you add it to the original one, would give a resultant vector that is 80.0 units long and points entirely in the −x direction. Specify the direction of the vector.
You are given a vector in the xy plane that has a magnitude of 86.0 units...
You are given a vector in the xy plane that has a magnitude of 86.0 units and a y component of -55.0 units. a.)What are the two possibilities for its x component? b.)Assuming the x component is known to be positive, specify the magnitude of the vector which, if you add it to the original one, would give a resultant vector that is 80.0 units long and points entirely in the ?x direction. c.)Specify the direction of the vector.
You are given a vector in the xy plane that has a magnitude of 89.0 units...
You are given a vector in the xy plane that has a magnitude of 89.0 units and a y component of -64.0 units. A) Assuming the x component is known to be positive, specify the magnitude of the vector which, if you add it to the original one, would give a resultant vector that is 80.0 units long and points entirely in the −x direction. B) Specify the direction of the vector.
Vectors a and b lie in an xy plane. a has magnitude 5.7 and angle 130...
Vectors a and b lie in an xy plane. a has magnitude 5.7 and angle 130 degrees relative to +x direction; b has components Bx = -5.34 and By = -4.37. What are the angles between the negative direction of the y axis and (a) the direction of a , (b) the direction of the product a x b , and (c) the direction of a x (b + 3.00k) ?
a.) Suppose that there is a constant magnetic field in the xy-plane with magnitude 0.5 T,...
a.) Suppose that there is a constant magnetic field in the xy-plane with magnitude 0.5 T, and a proton is moving with a speed of 3 × 10^5 m/s at a 45◦ angle relative to the field. What is the magnitude of the acceleration of the proton assuming it only experiences the force due to the magnetic field? b.) Inside of any microwave, there is a tube called a magnetron in which electrons orbit an approximately constant magnetic field. The...
Find a vector perpendicular to the line 2y=5-3x in the xy-plane.
Find a vector perpendicular to the line 2y=5-3x in the xy-plane.
1,Let v=(1,1)v=(1,1) be a vector in the xy-plane. Find a planar vector w which has length...
1,Let v=(1,1)v=(1,1) be a vector in the xy-plane. Find a planar vector w which has length 2√2, has a positive first component and is perpendicular to v. W=(,) 2, Find the points where the line l(t)=(1−t,1+t,t) intersects the plane z=x+y (Give the answer in the form of comma separated list of points like (*,*,*), (*,*,*)
The vector position of a 3.70 g particle moving in the xy plane varies in time...
The vector position of a 3.70 g particle moving in the xy plane varies in time according to r1 = (3î + 3ĵ)t + 2ĵt2 where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.80 g particle varies as r2 = 3î − 2ît2 − 6ĵt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s. rcm = cm (b)...
The vector position of a 3.95 g particle moving in the xy plane varies in time...
The vector position of a 3.95 g particle moving in the xy plane varies in time according to r1 = (3î + 3ĵ)t + 2ĵt2 where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.70 g particle varies as r2 = 3î − 2ît2 − 6ĵt. (a)Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s. rcm = cm (b)Determine the...
The vector position of a 3.90 g particle moving in the xy plane varies in time...
The vector position of a 3.90 g particle moving in the xy plane varies in time according to r1 = 3i + 3j t + 2jt2 where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.00 g particle varies as r2 = 3i − 2it2 − 6jt. (a) Determine the vector position of the center of mass at t = 2.40. (b) Determine the linear momentum of the system at...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT