Question
In: Physics
The vector position of a 3.70 g particle moving in the xy plane varies in time...
The vector position of a 3.70 g particle moving in the xy plane varies in time according to
r1 = (3î + 3ĵ)t + 2ĵt2
where t is in seconds and
r
is in centimeters. At the same time, the vector position of a 5.80 g particle varies as
r2 = 3î − 2ît2 − 6ĵt.
(a)
Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s.
rcm =
cm
(b)
Determine the linear momentum (in g · cm/s) of the system at t = 2.90 s.
p =
g · cm/s
(c)
Determine the velocity (in cm/s) of the center of mass at t = 2.90 s.
vcm =
cm/s
(d)
Determine the acceleration (in cm/s2) of the center of mass at t = 2.90 s.
acm =
cm/s2
(e)
Determine the net force (in µN) exerted on the two-particle system at t = 2.90 s.
Fnet =
µN
Solutions
genius_generous answered 2 years agoRelated Solutions
The vector position of a 3.95 g particle moving in the xy plane varies in time...
The vector position of a 3.95 g particle moving in the
xy plane varies in time according to
r1 = (3î +
3ĵ)t +
2ĵt2
where t is in seconds and r is in
centimeters. At the same time, the vector position of a 5.70 g
particle varies as
r2 = 3î −
2ît2 −
6ĵt.
(a)Determine the vector position (in cm) of the center of mass
of the system at t = 2.90 s.
rcm = cm
(b)Determine the...
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The vector position of a 3.90 g particle moving in the xy plane varies in time...
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