In: Statistics and Probability
The method of tree ring dating gave the following years A.D. for an archaeological excavation site. Assume that the population of x values has an approximately normal distribution.
1264 | 1285 | 1313 | 1187 | 1268 | 1316 | 1275 | 1317 | 1275 |
(a) Use a calculator with mean and standard deviation keys to find the sample mean year x and sample standard deviation s. (Round your answers to the nearest whole number.)
x = | A.D. |
s = | yr |
(b) Find a 90% confidence interval for the mean of all tree ring
dates from this archaeological site. (Round your answers to the
nearest whole number.)
lower limit | A.D. |
upper limit | A.D. |
Answer: The method of tree ring dating gave the following years A.D. for an archaeological excavation site. Assume that the population of x values has an approximately normal distribution.
1264 1285 1313 1187 1268 1316 1275 1317 1275
Solution:
a) the sample mean year x and sample standard deviation s.
Sample mean:
Mean, x̄ = Σx/n
x̄ = Σ(1264 +1285 +.....+ 1275)/9
x̄ = 11500/9
x̄ = 1277.77
Mean, x̄ = 1278
Sample standard deviation, s
S = √(Σ(x-x2)/n-1)
S = √(1264-1278)+......(1275-1278)/9-1
S = √12834/8
S = 40.05309
Therefore,
Mean, x̄ = 1278 A.D
S = 40 yr
(b) 90% confidence interval for the mean of all tree ring dates from this archaeological site.
df = n- 1 = 9 - 1 = 8
At 90% confidence interval
t(α/2,df) = 1.859 = 1.860
Therefore,
E = tα * S/√n
E = 1.860 * 40/√9
E = 74.40/ 3
E=24.80
Therefore,
(x̄ – E < μ < x̄ + Ε)
(1278 - 24.80 < μ < 1278 + 24.80 )
(1253.20 < μ < 1302.80)
(1253 < μ < 1303 )
Therefore,
Lower Limit = 1253 AD
Upper Limit = 1303 AD