In: Math
A car company claims to only have a carbon dioxide emissions of .7. You think it’s higher. You collect 100 cars and test the carbon dioxide. You find an average of .75 with a sample standard deviation of .1. Perform a test of hypothesis with an alpha of 10%.
Ho :   µ =   0.7  
           
   
Ha :   µ >   0.7  
    (Right tail test)      
   
          
           
   
Level of Significance ,    α =   
0.10          
       
sample std dev ,    s =    0.1000  
           
   
Sample Size ,   n =    100  
           
   
Sample Mean,    x̅ =   0.7500  
           
   
          
           
   
degree of freedom=   DF=n-1=   99  
           
   
          
           
   
Standard Error , SE = s/√n =   0.1000   / √
   100   =   0.0100  
   
t-test statistic= (x̅ - µ )/SE = (   0.750  
-   0.7   ) /    0.010  
=   5.000
          
           
   
  
p-Value   =   0.0000   [Excel formula
=t.dist(t-stat,df) ]      
       
Decision:   p-value<α, Reject null hypothesis
          
           
Conclusion: There is enough evidence to reject the company's claim
at α=0.10.