Question

In: Math

A city has 10,000 households, and you have collected a simple random sample size of 25...

A city has 10,000 households, and you have collected a simple random sample size of 25 from the households in this city and measured how much each household paid in school taxes in 2012. For this sample, X = $2500, and s = $ 1000. You wish to construct a 95% confidence interval for μ.

Solutions

Expert Solution

Solution :

Given that,

sample mean = = $2500

sample standard deviation = s = $1000

sample size = n = 25

Degrees of freedom = df = n - 1 = 25 - 1 = 24

At 95% confidence level

= 1 - 95%

=1 - 0.95 =0.05

/2 = 0.025

t/2,df = 0.025 , 24 = 2.064

Margin of error = E = t/2,df * (s /n)

= 2.064* (1000 / 25)

Margin of error = E =412.8

The 95% confidence interval estimate of the population mean is,

- E < < + E

2500 - 412.8 < < 2500 +412.8

2087.2 < < 2912.8

(2087.2 ,  2912.8)


Related Solutions

A simple random sample has a sample size of n = 65. Given the population is...
A simple random sample has a sample size of n = 65. Given the population is normally distributed, find the critical value ta/2 corresponding to a 99% confidence level. a) 2.678 b) 2.575 c) 2.000 d) 2.660
The sample data below have been collected based on a simple random sample from a normally...
The sample data below have been collected based on a simple random sample from a normally distributed population. Complete parts a and b. 5 4 0 5 7 6 9 0 8 4 a. Compute a 98% confidence interval estimate for the population mean. The 98% confidence interval for the population mean is from to . (Round to two decimal places as needed. Use ascending order.) b. Show what the impact would be if the confidence level is increased to...
How to draw a simple random sample of size 9 and a systematic sample of size...
How to draw a simple random sample of size 9 and a systematic sample of size 9 from 45 samples size. can you explain the steps for each selected sample for me . thanks
The mean tar content of a simple random sample of 25 unfiltered king-size cigarettes is 20.8...
The mean tar content of a simple random sample of 25 unfiltered king-size cigarettes is 20.8 mg, with a standard deviation of 4 mg. The mean tar content of a simple random sample of 25 filtered 100 mm cigarettes is 13.4 mg with a standard deviation of 3.9 mg. Assume that the two samples are independent, simple, random samples, selected from normally distributed populations. Do not assume that the population standard deviations are equal. o Use a 0.05 significance level...
In a simple random sample of 100 households, the sample mean number of personal computers was...
In a simple random sample of 100 households, the sample mean number of personal computers was 1.32. Assume the population standard deviation is 0.41. Construct a 95% confidence interval for the mean number of personal computers. (a) (1.24, 1.40) (b) (1.25, 1.39) (c) (0.15, 0.67) (d) (0.19, 0.63)
A university has 15,000 students. We have drawn a simple random sample size of 400 from...
A university has 15,000 students. We have drawn a simple random sample size of 400 from the population and recorded how much money each student spent on cellular telephone service during November 2003. For this sample, the sample mean is $36, and sample standard deviation is $20. At a 99% level of confidence, test the null hypothesis that these 15,000 students, combined, did not spend more than $500,000 on cellular telephone service during November 2003.
suppose a random sample of 137 households in a city was selected to determine the average...
suppose a random sample of 137 households in a city was selected to determine the average annual household spending on food at home for city residents. The sample results are contained in the accompanying table. Complete parts a and b below. a. Using the sample standard deviation as an estimate for the population standard​ deviation, calculate the sample size required to estimate the true population mean to within ±25 with 90​% confidence. How many additional samples must be​ taken? The...
A random sample of 250 households in a large city revealed that the mean number of...
A random sample of 250 households in a large city revealed that the mean number of televisions per household was 2.76 From previous analyses we know that the population standard deviation is 1.8. a) State the appropriate hypotheses, if we wish to determine that the true mean number of televisions per household is at least 2.5. b) Test the hypotheses at the 10% significance level and explain your conclusion.
You take a simple random sample of size 64 from a population with a mean of...
You take a simple random sample of size 64 from a population with a mean of 100 and a standard deviation of 32. A. The standard error of ഥX is ______________. What is the probability that ഥX will be: B. Less than 110? ___________________ C. Greater than 96? __________________ D. Within 1.7 standard errors of M? ____________ please help
The number of successes and the sample size are given for a simple random sample from...
The number of successes and the sample size are given for a simple random sample from a population. Use the one-proportion z-interval procedure to find the required confidence interval. n = 76, x = 31; 98% level 0.298 to 0.518 0.276 to 0.540 0.297 to 0.519 0.277 to 0.539 Use the one-proportion z-interval procedure to find the required confidence interval. A researcher wishes to estimate the proportion of adults in the city of Darby who are vegetarian. In a random...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT