In: Statistics and Probability
suppose a random sample of 137 households in a city was selected to determine the average annual household spending on food at home for city residents. The sample results are contained in the accompanying table. Complete parts a and b below.
a. Using the sample standard deviation as an estimate for the population standard deviation, calculate the sample size required to estimate the true population mean to within ±25 with 90% confidence. How many additional samples must be taken? The required sample size = (Round up to the nearest whole number.)
The number of additional samples required = (Type a whole number.)
b. Using the sample standard deviation as an estimate for the population standard deviation, calculate the sample size required to estimate the true population mean to within ±25 with 95% confidence. How many additional samples must be taken? The required sample size = (Round up to the nearest whole number.)
The number of additional samples required = (Type a whole number.)
3354.71 |
3356.05 |
3359.66 |
3361.93 |
3371.03 |
3373.35 |
3379.17 |
3385.93 |
3386.54 |
3386.59 |
3403.63 |
3403.92 |
3406.33 |
3407.93 |
3412.38 |
3424.34 |
3431.89 |
3435.35 |
3441.93 |
3451.66 |
3462.73 |
3468.88 |
3481.77 |
3493.92 |
3498.85 |
3510.82 |
3515.93 |
3517.79 |
3521.48 |
3524.25 |
3536.37 |
3541.73 |
3545.12 |
3555.52 |
3563.25 |
3570.95 |
3589.53 |
3593.76 |
3594.24 |
3626.87 |
3628.35 |
3655.42 |
3662.61 |
3663.29 |
3675.65 |
3688.14 |
3727.01 |
3736.53 |
3740.61 |
3775.27 |
3787.64 |
3894.02 |
3922.98 |
the sample standard deviation of the given data using excel is 142.567 since the sample standard deviation as an estimate for the population standard deviation so = 142.567
1 ) z at 90% = 1.645
Margin of error (E) = 25
= = 88
The required sample size =88
The number of additional samples required = 137-88 = 49
2 )
z at 90% = 1.96
Margin of error (E) = 25
= = 125
The required sample size =125
The number of additional samples required = 137-125= 12