In: Math
2. a. Use signifcance test to test the indicated claim. A standard aptitude test is given to several randomly selected programmers, and the scores are given below for the mathematics and verbal portions of the test. At the 0.05 level of significance, test the claim that programmers do better on the mathematics portion of the test.
Mathematics 447 540 427 456 527 449 477 498 425
Verbal 385 478 343 371 440 371 394 422 385
b. Find a 90% confidence interval for the difference of the mean.
Here we have data:
Mathematics | Verbal |
447 | 385 |
540 | 478 |
427 | 343 |
456 | 371 |
527 | 440 |
449 | 371 |
477 | 394 |
498 | 422 |
425 | 385 |
Excel output for hypotheses test:
t-Test: Two-Sample Assuming Unequal Variances | ||
Variable 1 | Variable 2 | |
Mean | 471.7777778 | 398.7777778 |
Variance | 1749.194444 | 1696.444444 |
Observations | 9 | 9 |
Hypothesized Mean Difference | 0 | |
df | 16 | |
t Stat | 3.730862424 | |
P(T<=t) one-tail | 0.00090991 | |
t Critical one-tail | 1.745883676 | |
P(T<=t) two-tail | 0.001819821 | |
t Critical two-tail | 2.119905299 |
a) Hypotheses
Ho: μ1 = μ2
Ha: μ1 >μ2
Test statistics :
t = 3.73
Critical value:
t-critical = 1.75
Conclusion: Reject the null hypothesis, here we have sufficient evidence to reject the null hypothesis because t-observed value (3.73) is grater than t-critical value (1.75). We can say that mathematics portion is batter than verbal.
b)