Question

A projectile is launched at 40.0 m/s at an angle 30 degree from ground to ground. o Write a function that will return the time of flight based on V_{0} and theta. o Find N time split (suppose N=20) and put those time in Tf[]. o Calculate the height y of the projectile for those time and put them in Y[]. C++

Answer 1

Solution :

Following is the C++ code for the problem :

#include <iostream>
#include <cmath>

using namespace std;

const double PI = 3.141592654, g = -9.81 ;
const int N=20;

float time_of_flight(float v,float angle)
{
    float time=fabs((2*v*sin((angle*PI)/180))/g);
    return time;
}
int main()

{
    
    float launch_angle, Vo,tof,tf[20],y[20];
    Vo=40.0;
    launch_angle=30;
    tof=time_of_flight(Vo,launch_angle);
    cout<<"The time of flight is : "<<tof<<endl;
    float increment=tof/20;

    cout<<"Following are the position of projectile at N(20) different time intervals"<<endl;
    cout<<"  Time\t\tHeight"<<endl;
    for(int i=0;i<N-1;i++)
    {
    if(i==0)
    tf[i]=increment;
    else
    {
        tf[i]=tf[i-1]+increment;
    }
    y[i]=Vo*sin(launch_angle*PI/180)*tf[i]+0.5*g*tf[i]*tf[i];
    cout<< tf[i]<<"        "<<y[i]<<endl;
    }
    return 0;
}

Code demo :

Output :