Question

.A balloon holds 36.7 kg of helium. What is the volume of the balloon if the pressure is 1.14 atm and the temperature is 23 °C? 2.STP (standard temperature and pressure) is used as a reference point for the molar volume of an ideal gas. In the USA, most chemists, most general chemistry texts, and OWL use STP = 0°C, 1 atm, where the molar volume = 22.4 L/mol. If the reference pressure is chosen to be 1 bar, the molar volume is 22.7 L/mol. Do not confuse the two.A 1.23 mol sample of argon gas occupies a volume of L at STP 3.A 9.84 L sample of gas has a pressure of 0.939 atm and a temperature of 75 °C. The sample is compressed to a volume of 8.80 L and is cooled to 24 °C. Calculate the new pressure of the gas, assuming that no gas escaped during the experiment in atm 4.A sample of gas has a volume of 3.56 L at a temperature of 53.00 °C. The gas sample is heated to a temperature of 138.00 °C (assume pressure and amount of gas are held constant). Predict whether the new volume is greater or less than the original volume, and calculate the new volume. 5.A sample of gas has a volume of 635 mL at a pressure of 4.61 atm. The gas is compressed and now has a pressure of 7.14 atm. Predict whether the new volume is greater or less than the initial volume, and calculate the new volume. Assume temperature is constant and no gas escaped from the container.

Answer 1

1) .A balloon holds 36.7 kg of helium. What is the volume of the balloon if the pressure is 1.14 atm and the temperature is 23 °C

mass of He = 36.7 kg = 36700 g

moles of He = mass / molar mass

                   = 36700/4

                  = 9175

P = 1.14 atm

T = 23 + 273 = 296 K

P V = n R T

1.14 x V = 9175 x 0.0821 x 296

V = 1.96 x 10^5 L

volume = 1.96 x 10^5 L

2) this problem is not clear

3.)

A 9.84 L sample of gas has a pressure of 0.939 atm and a temperature of 75 °C. The sample is compressed to a volume of 8.80 L and is cooled to 24 °C. Calculate the new pressure of the gas

V1 = 9.84 L , P1 = 0.939 atm , T1 = 75 + 273 = 348 K

V2 = 8.80 L , P2 = ?   , T2 = 24 + 273 = 297 K

P1 V1 / T1 = P2 V2 / T2

0.939 x 9.84 / 348 = P2 x 8.80 / 297

P2 = 0.896 atm

pressure = 0.896 atm